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$The apration Delta is defined as xay=2xy+3 in modilo arithmotic /_\. a) Sraw a table for grad on the set {5,7,9,10} (b) From your hable (i) Fraduale 7grad) ii) find the brubl set of a a(a+2) =8 2. A binary uperation 0 is defined on the set of real numbers by a 0 bo =(a-1)/(b)+b, make x the subject x@r=-3, factorising your answ -er completely. Solvtion$

The apration $\Delta$ is defined as $x a y=2 x y+3$ in modilo arithmotic $\triangle$ . $\newline$ a) Sraw a table for \(\newlineabla \) on the set $\{5,7,9,10\}$ $\newline$ (b) From your hable $\newline$ (i) Fraduale 7 \(\newlineabla) \) $\newline$ ii) find the brubl set of a $a(a+2)$ $=8$ $\newline$ $2$ . A binary uperation $0$ is defined on the set of real numbers by a $0$ bo $=\frac{a-1}{b}+b$ , make $x$ the subject $\newline$ $x a y=2 x y+3$ $0$ , factorising your answ -er completely. $\newline$ Solvtion

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Transformations of functions

Full solution

Q. The apration

\Delta

is defined as

x a y=2 x y+3

in modilo arithmotic

\triangle

.

\newline

a) Sraw a table for \(\newlineabla \) on the set

\{5,7,9,10\}

\newline

(b) From your hable

\newline

(i) Fraduale 7 \(\newlineabla) \)

\newline

ii) find the brubl set of a

a(a+2)

=8

\newline

2

. A binary uperation

0

is defined on the set of real numbers by a

0

bo

=\frac{a-1}{b}+b

, make

x

the subject

\newline

x a y=2 x y+3

0

, factorising your answ -er completely.

\newline

Solvtion

Check choices: Check the choices for the correct reflection function. $g(x) = 4x + 1$ matches one of the choices.

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g(x)

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Question

What kind of transformation converts the graph of

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Question

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\newline

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Question

\lim _{x \rightarrow \frac{\pi}{4}} \cos (x)=?

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Question

Tess tried to solve the differential equation

\frac{d y}{d x}=2 x y-6 x

. This is her work:

\newline

\frac{d y}{d x}=2 x y-6 x

\newline

1

\quad \frac{d y}{d x}=(y-3) 2 x

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2

\quad \int \frac{1}{y-3} d y=\int 2 x d x

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3

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4

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5

\quad|y-3|=e^{x^{2}}+C_{1}

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6

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7

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(A) Tess's work is correct.

\newline

1

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\newline

4

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\newline

7

is incorrect. Tess didn't account for adding

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Question

Aditya tried to solve the differential equation

\frac{d y}{d x}=6 x-30

. This is his work:

\newline

\frac{d y}{d x}=6 x-30

\newline

1

\quad \int 30 d y=\int 6 x d x

\newline

2

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3

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\newline

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1

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2

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of the following expressions represents the distance between the sandbag and the target?

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Question

f(x) = -(x+1)(x+7)

\newline

The function represents a parabola in the

xy

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f

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\newline

1

\newline

f(x) = -(x+4)^{2}+9

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Determine whether the function

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\newline

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f(x)

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