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Transformations of functions

Managed bookmarks\newline(589589) YouTube\newlineCell Diagram:\newlineUT News - The Univ...\newlineHistory\newlineEsperanza Rising (55) New Tab\newlineMandatory District...\newlineDistrict Student Trai...\newlinewhat's another wor...\newlineDeltaMath\newline← \leftarrow Back to Home\newlineReg Precal cycle 66( will add more)\newlineDue: May 1414 at 88:0000 AM\newlineGrade: 35% 35 \% \newlineAdding Vectors Commutatively [Guided]\newlineAdding Vectors Numerically\newlineVector Components from Initial / Terminal Points\newlineMagnitude from Initial / Terminal Points\newlineMultiply Vector By Scalar Graphically\newlineMultiply Vector By Scalar\newlineFind Vector Magnitude and Direction\newlineDouble Angle [Sine / Cosine]\newlineAngle Sum and Difference\newlineAngle Sum and Difference: Tangent\newlineReciprocal Trig Identities\newlineCalculator\newlineDonovan Kennedy\newlineAngle Sum and Difference: Tangent\newlineScore: 0/5 0 / 5 Penalty: 11 off\newlineQuestion\newlineShow Examples\newlineIf cos⁡A=4041 \cos A=\frac{40}{41} and sin⁡B=2029 \sin B=\frac{20}{29} and angles A \mathrm{A} and B \mathrm{B} are in Quadrant I, find the value of tan⁡(A+B) \tan (A+B) .\newlineAnswer Attempt 22 out of 22\newline941 \frac{9}{41} \newlineSubmit Answer\newlineStill Stuck?\newlineCopyright Q20242024 DeltaMath.com All Rights Reserved. Privacy Policy | Terms of Service\newlineCopyrisht E20242024 Delta Math.com All Rights Reserved. Privacy Policy / Termis of Service\newlineType here to search
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b) If U={1,2,3,… U=\{1,2,3, \ldots , (ii) A∪Aˉ A \cup \bar{A} \newline(i) Aˉ \bar{A} \newlineCreative section\newline(ii) A−(A∩B)=(A∪B)−B \mathrm{A}-(\mathrm{A} \cap \mathrm{B})=(\mathrm{A} \cup \mathrm{B})-\mathrm{B} verify that:\newline(i) A∪(A∩B)=A∩(A∪B) A \cup(A \cap B)=A \cap(A \cup B) \newline(iv) (A∪B)−(A∩B)=(A−B)∪(B−A) (A \cup B)-(A \cap B)=(A-B) \cup(B-A) \newline(iii) A∪(B−A)=B∪(A−B) A \cup(B-A)=B \cup(A-B) \newlineb) If U={0,1,2,…,10},A={2,3,5,7} U=\{0,1,2, \ldots, 10\}, A=\{2,3,5,7\} and B={1,3,5,7,9} B=\{1,3,5,7,9\} , verify the followis operations.\newline(i) A∪B‾=Aˉ∩Bˉ \overline{A \cup B}=\bar{A} \cap \bar{B} \newline(ii) A∪Aˉ A \cup \bar{A} 00\newlinec) If a universal set A∪Aˉ A \cup \bar{A} 11 amp A∪Aˉ A \cup \bar{A} 22, prove that.\newline(i) A∪Aˉ A \cup \bar{A} 33\newline(ii) A∪Aˉ A \cup \bar{A} 44
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Знайди об'єм тіла, отриманого при обертанні навколо осі абсцис криволінійної трапеції, обмеженої лініями:\newliney=x2+12,x=0,x=4,y=0 y=x^{2}+12, x=0, x=4, y=0
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22. Relaciona cada polinomio aritmético con su respectiva solución:\newline\begin{tabular}{|c|c|}\newline\hline Polinomio aritmético & Solución \\\newline\hline 2+5+(−6)×3+(−12)+8÷(−2) 2+5+(-6) \times 3+(-12)+8 \div(-2) & 55 \\\newline\hline[2+5+(−6)]×3+(−12)+8÷(−2) [2+5+(-6)] \times 3+(-12)+8 \div(-2) & −27-27 \\\newline\hline 2+5+(−6)×3+[(−12)+8]÷(−2) 2+5+(-6) \times 3+[(-12)+8] \div(-2) & −17-17 \\\newline\hline 2+5+(−6)]×3+[(−12)+8]÷(−2) 2+5+(-6)] \times 3+[(-12)+8] \div(-2) & −13-13 \\\newline\hline 2+[5+(−6)]×3+(−12)+8÷(−2) 2+[5+(-6)] \times 3+(-12)+8 \div(-2) & −9-9 \\\newline\hline\newline\end{tabular}
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New Tab\newlineALEKS LTI 11.33\newlineALEKS - Brittney Smith - Pre\newlinewww-awu.aleks.com/alekscgi/x/IsI.exe/11o_u-IgNsIkr77j88P33jH-IQsBcJdknPrkicRI66pS66oAVbiQYFU22vvpW55CFgzs\newlineProctored Test 33 1616-Wks (Lectures 11−11-11)\newlineQuestion 1111 of 1818 (11 point) I Question Attempt: 11 of 11\newline≡1 \equiv 1 \newline=2 =2 \newline=3 =3 \newline44\newline≡5 \equiv 5 \newline66\newline77\newline88\newline99\newlineSuppose that the polynomial function f f is defined as follows.\newlinef(x)=2x2(x−4)2(x+7)3 f(x)=2 x^{2}(x-4)^{2}(x+7)^{3} \newlineList each zero of f f according to its multiplicity in the categories below.\newlineIf there is more than one answer for a multiplicity, separate them with commas. If there is no answer, click on
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Previous Problem\newlineProblem List\newlineNext Problem\newline77 Work Energy: Problem 33\newline(11 point)\newlineThe velocity of a 2.3 kg 2.3 \mathrm{~kg} particle changes from 4i−5jm/s 4 \mathbf{i}-5 \mathbf{j} \mathrm{m} / \mathrm{s} to −6i+3jm/s -6 \mathbf{i}+3 \mathbf{j} \mathrm{m} / \mathrm{s} .\newlineWhat is its change in kinetic energy?\newline−893.2 -893.2 \newlinePreview My Answers\newlineSubmit Answers\newlineYou have attempted this problem 22 times.\newlineYour overall recorded score is 0% 0 \% .\newlineYou have unlimited attempts remaining.\newlineEmail Instructor\newlineWeBWork \& 1996−2022 1996-2022 | the generated at 1111/0707/20232023 at 0606:0909pm EST\newline| theme: math 44 | ww_version: 22.1717 I pg_version 22.1717 | The WeBWork Project
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me:\newlineMora Quimanes\newlinePD:\newline55\newline33\newlineDate:\newline4/8/24 4 / 8 / 24 \newlineRTI - Practice Worksheet\newlineWrite the equation of the line given a graph\newlineWS11\newline11)\newline11. find the y y -intercept: A(−0,−1)B(−124) A(-0,-1) B(-124) \newline22. Find the slope, show work: \qquad Use two points A(0,−1) A(0,-1) and B(−2,4) B(-2,4) y1,y2x1,x2= \frac{y_{1}, y_{2}}{x_{1}, x_{2}}= \newline33. Write the equation in slope intercept form:\newlinefind the y y -intercept: \qquad \newline \qquad \newline \qquad Find the slope, show work: \qquad Use two points: y y 22 and y y 33\newliney1y2γ1γ2= \frac{y_{1} y_{2}}{\gamma_{1} \gamma_{2}}= \newlineWrite the equation in slope intercept form:\newline22)\newline11. find the y y -intercept: \qquad \newline22. Find the slope, show work: \qquad Use two points: y y 77 and y y 88 y y 99\newline33. Write the equation in slope intercept form:\newline44)\newline11. find the y y -intercept: \qquad A(−0,−1)B(−124) A(-0,-1) B(-124) 22\newline22. Find the slope, show work: \qquad \newlineUse two points: A(−0,−1)B(−124) A(-0,-1) B(-124) 44 and A(−0,−1)B(−124) A(-0,-1) B(-124) 55 A(−0,−1)B(−124) A(-0,-1) B(-124) 66\newline33. Write the equation in slope intercept form:
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|z1z_1|=\sqrt{1717},|z2z_2|=22\sqrt{22},|3z1+z23z_1+z_2|=\sqrt{221221},P=∣z2+z1−z1z2∣P=|z_2+z_1-z_1z_2|. Find exact value of PP
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Determine relative extrema algebraically.\newlineWilliam Artiaga 0404/1818/2424 1212:3535 AM\newline−2-2−4-4 Determine\newlineThis quiz: 55 point(s) possible\newlineThis question: 11 point(S) possible\newlineResume later\newlinealgebraically.\newlineQuestion 33 of 55\newlineSubmit quiz\newlineFind the xx-values of all points where the function has any relative extrema. Find the value(s) of any relative extrema.\newlinef(x)=5+(4+3x)23f(x)=5+(4+3x)^{\frac{2}{3}}\newlineA. There are no relative minima. The function has a relative maximum of \newlineoxed{} at \newlinex=x= \newlineoxed{} T.\newline(Use a comma to separate answers as needed.)\newlineB. There are no relative maxima. The function has a relative minimum of \newlineoxed{} at \newlinex=x= \newlineoxed{}\newline(Use a comma to separate answers as needed.)\newlineC. The function has a relative maximum of \newlineoxed{} at \newlinex=x= \newlineoxed{} and a relative minimum of \newlineoxed{} at \newlinex=x= \newlineoxed{} \newlineoxed{}\newline(Use a comma to separate answers as needed.)\newlineD. There are no relative extrema.
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11. Diketahui f(x)=2x+5 \mathrm{f}(\mathrm{x})=2 \mathrm{x}+5 dan g(x)=x−1x+4,x≠−4 \mathrm{g}(\mathrm{x})=\frac{x-1}{x+4}, x \neq-4 , maka (fog)(x)=… (\mathrm{fog})(\mathrm{x})=\ldots \newline22. Fungsi f f dan g g adalah pemetaan dari R R ke R R yang dirumuskan oleh f(x)= f(x)= 3x+5 3 \mathrm{x}+5 dan g(x)=2xx+1,x≠−1 \mathrm{g}(\mathrm{x})=\frac{2 x}{x+1}, x \neq-1 . Rumus (gof)(x) adalah g(x)=x−1x+4,x≠−4 \mathrm{g}(\mathrm{x})=\frac{x-1}{x+4}, x \neq-4 00\newline33. Diketahui fungsi g(x)=x−1x+4,x≠−4 \mathrm{g}(\mathrm{x})=\frac{x-1}{x+4}, x \neq-4 11 dan g(x)=x−1x+4,x≠−4 \mathrm{g}(\mathrm{x})=\frac{x-1}{x+4}, x \neq-4 22. Nilai komposisi fungsi g(x)=x−1x+4,x≠−4 \mathrm{g}(\mathrm{x})=\frac{x-1}{x+4}, x \neq-4 33 adalah ...\newline44. Diketahui fungsi g(x)=x−1x+4,x≠−4 \mathrm{g}(\mathrm{x})=\frac{x-1}{x+4}, x \neq-4 44, dan g(x)=x−1x+4,x≠−4 \mathrm{g}(\mathrm{x})=\frac{x-1}{x+4}, x \neq-4 55. Nilai komposisi fungsi g(x)=x−1x+4,x≠−4 \mathrm{g}(\mathrm{x})=\frac{x-1}{x+4}, x \neq-4 66\newlineLATIHAN\newline55. Diketahui fungsi-fungsi g(x)=x−1x+4,x≠−4 \mathrm{g}(\mathrm{x})=\frac{x-1}{x+4}, x \neq-4 77 didefinisikan dengan g(x)=x−1x+4,x≠−4 \mathrm{g}(\mathrm{x})=\frac{x-1}{x+4}, x \neq-4 88 g(x)=x−1x+4,x≠−4 \mathrm{g}(\mathrm{x})=\frac{x-1}{x+4}, x \neq-4 99 didefinisikan dengan (fog)(x)=… (\mathrm{fog})(\mathrm{x})=\ldots 00. Hasil dari fungsi (fog)(x)=… (\mathrm{fog})(\mathrm{x})=\ldots 11 adalah ...\newline66. Diketahui (fog)(x)=… (\mathrm{fog})(\mathrm{x})=\ldots 22 dirumuskan oleh (fog)(x)=… (\mathrm{fog})(\mathrm{x})=\ldots 33 dan (fog)(x)=… (\mathrm{fog})(\mathrm{x})=\ldots 44 −6-6 . Jika (fog)(x)=… (\mathrm{fog})(\mathrm{x})=\ldots 55, nilai (fog)(x)=… (\mathrm{fog})(\mathrm{x})=\ldots 66\newline77. Diketahui (fog)(x)=… (\mathrm{fog})(\mathrm{x})=\ldots 22 dirumuskan oleh (fog)(x)=… (\mathrm{fog})(\mathrm{x})=\ldots 88 dan (fog)(x)=… (\mathrm{fog})(\mathrm{x})=\ldots 99 f f 00. Jika f f 11, maka nilai f f 22 yang memenuhi adalah ...\newline88. Jika f f 33 dan f f 44, maka f f 55\newline99. Diketahui f f 66 dan f f 77. Rumus fungsi f f 88 adalah...\newline1010. Suatu pemetaan (fog)(x)=… (\mathrm{fog})(\mathrm{x})=\ldots 22 dengan g g 00 dan g g 11, maka g g 22
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Tugas Mandiri 22\newline11. Obligasi dengan nilai nominal 100100.000000 , tingkat bunga obligasi 8% 8 \% , berjangka waktu 33 tahun, diterbitkan tg⁡ \operatorname{tg} 1/1/2005 1 / 1 / 2005 . Bunga dibayarkan setiap tanggal 1/1,1/5 1 / 1,1 / 5 dan 1/9 1 / 9 . Hitunglah nilai jual obligasi, buatlah tabel amortisasi dan buatlah jurnal pada tanggal 11 Januari 20052005, 11 Mei 20052005, 11 September 20052005, 3131 Desember 20052005, dan 11 Januari 20062006. Jika pada saat diterbitkan tingkat bunga pasar sebesar :\newlinea. 9% 9 \% \newlineb. 6% 6 \% \newline22. Bila obligasi pada point 11 diatas dilunasi pada tanggal 1/1/2007 1 / 1 / 2007 dengan harga pelunasan 110110.000000 .. Buatlah jurnalnya. Jika pada saat diterbitkan tingkat bunga pasar sebesar :\newlinea. 9% 9 \% \newlineb. 6% 6 \%
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