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Terrence is a scientist who works with the Department of Agriculture. In order to ensure a good harvest, Terrence keeps track of various local caterpillar populations. He catches 750750 caterpillars, marks them, and releases them. Then later, he catches 400400 caterpillars, 1212 of which are marked. To the nearest whole number, what is the best estimate for the caterpillar population?

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Q. Terrence is a scientist who works with the Department of Agriculture. In order to ensure a good harvest, Terrence keeps track of various local caterpillar populations. He catches 750750 caterpillars, marks them, and releases them. Then later, he catches 400400 caterpillars, 1212 of which are marked. To the nearest whole number, what is the best estimate for the caterpillar population?
  1. Set up proportion: Set up the proportion based on the mark and recapture data.\newlineMarked caterpillars found: 1212\newlineTotal caterpillars in second catch: 400400\newlineTotal caterpillars marked initially: 750750\newlineLet p p be the estimated caterpillar population.\newlineThe proportion is:\newlinemarked caterpillars foundtotal caterpillars in second catch=total caterpillars marked initiallyestimated caterpillar population \frac{\text{marked caterpillars found}}{\text{total caterpillars in second catch}} = \frac{\text{total caterpillars marked initially}}{\text{estimated caterpillar population}} \newline12400=750p \frac{12}{400} = \frac{750}{p}
  2. Solve for p: Solve for p p by cross-multiplying.\newline12p=750400 12 \cdot p = 750 \cdot 400 \newline12p=300000 12p = 300000
  3. Divide to isolate p: Divide both sides by 1212 to isolate p p .\newlinep=30000012 p = \frac{300000}{12} \newlinep=25000 p = 25000

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