Substitution by parts: blem 10t)ate the indefinite integral.)xsin2(5x)dx=□+C.Hint: Integrate by parts with u=x.gauss.vaniercollege.qc.cagauss.vaniercollege.qc.ca
Q. Substitution by parts: blem 10t)ate the indefinite integral.)xsin2(5x)dx=□+C.Hint: Integrate by parts with u=x.gauss.vaniercollege.qc.cagauss.vaniercollege.qc.ca
Identify u and dv: Let's use integration by parts where u=x and dv=sin2(5x)dx.
Find du and v: First, we need to find du and v.du=dx and for v, we need to integrate sin2(5x)dx.
Integrate sin2(5x): To integrate sin2(5x), use the power reduction formula: sin2(θ)=21−cos(2θ).So, ∫sin2(5x)dx=∫21−cos(10x)dx.
Apply power reduction formula: Now integrate: ∫(21)dx−∫(2cos(10x))dx=(2x)−(20sin(10x))+C. So, v=(2x)−(20sin(10x)).
Calculate v: Now apply integration by parts: ∫udv=uv−∫vdu. Plug in u, du, and v: \int x\sin^{\(2\)}(\(5x)\,dx = x\left(\frac{x}{2} - \frac{\sin(10x)}{20}\right) - \int\left(\frac{x}{2} - \frac{\sin(10x)}{20}\right)dx.
Apply integration by parts: Simplify the integral: x\left(\frac{x}{\(2\)} - \frac{\sin(\(10\)x)}{\(20\)}\right) - \int\left(\frac{x}{\(2\)}\right)dx + \int\left(\frac{\sin(\(10\)x)}{\(20\)}\right)dx.
Simplify the integral: Integrate each part: \(\frac{x^2}{2} - 20xsin(10x) - 4x2 + 200cos(10x) + C.
Integrate each part: Combine like terms: (4x2)−(20xsin(10x))+(200cos(10x))+C.
Combine like terms: Oops, made a mistake in the integration by parts formula. It should be uv−∫vdu, not uv−∫udv. Let's correct that.
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