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Math Problems
Calculus
Find indefinite integrals using the substitution
Write the equation of all horizontal asymptotes of the function
f
(
x
)
=
6
x
−
e
x
3
x
−
2
x
2
f(x)=\frac{6x-e^{x}}{3x-2x^{2}}
f
(
x
)
=
3
x
−
2
x
2
6
x
−
e
x
.
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12
12
12
. In the graphical method of obtaining quartiles, which of the following diagram is used (a) Pie chart (b) Ogive (c) Bar chart (d) Histogram
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The graph of
y
=
3
2
(
x
+
2
)
2
−
6
y=\frac{3}{2}(x+2)^{2}-6
y
=
2
3
(
x
+
2
)
2
−
6
is shown in the
x
y
x y
x
y
-plane. Which of the following characteristics of the graph is displayed as a constant or
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Page No.
\newline
Date:
\newline
Find the treth set of the following simultaneus equation
\newline
5
x
6
−
3
4
y
=
1
2
×
2
3
y
=
5
2
{\frac{5x}{6}-\frac{3}{4}y=\frac{1}{2}\times\frac{2}{3}y=\frac{5}{2}}
6
5
x
−
4
3
y
=
2
1
×
3
2
y
=
2
5
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Evaluate the indefinite integral given below.
\newline
∫
x
(
x
−
6
)
6
d
x
\int x(x-6)^{6} d x
∫
x
(
x
−
6
)
6
d
x
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∫
d
x
25
+
4
x
2
\int \frac{d x}{\sqrt{25+4 x^{2}}}
∫
25
+
4
x
2
d
x
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Use Green's theorem to evaluate the line integral along the given positively oriented curve,
∫
C
7
y
3
d
x
−
7
x
3
d
y
,
is the circle
x
2
+
y
2
=
4
\int_{C}7y^{3}\,dx-7x^{3}\,dy,\quad \text{is the circle } x^{2}+y^{2}=4
∫
C
7
y
3
d
x
−
7
x
3
d
y
,
is the circle
x
2
+
y
2
=
4
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Use Green's theorem to evaluate the line integral along the given positively oriented curve.
\newline
∫
C
7
y
3
d
x
−
7
x
3
d
y
,
C
is the circle
x
2
+
y
2
=
4
\int_{C} 7 y^{3} d x-7 x^{3} d y, \quad C \text { is the circle } x^{2}+y^{2}=4
∫
C
7
y
3
d
x
−
7
x
3
d
y
,
C
is the circle
x
2
+
y
2
=
4
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Kiana Rosenthat-Wright
05
/
03
/
24
05 / 03 / 24
05/03/24
\newline
HW Soore:
52
,
3
E
t
2
38.67
52,3 \mathrm{Et}^{2} 38.67
52
,
3
Et
2
38.67
of
7
7
7
\newline
9.4.3
⋅
5
9.4 .3 \cdot 5
9.4.3
⋅
5
\newline
points
\newline
Points:
0
0
0
of
\newline
Calculate the weight of the piece of steel shown in the drawing. (This steel weighs
0.283
l
b
i
n
I
3
0.283 \mathrm{lb}^{\mathrm{in}} \mathrm{I}^{3}
0.283
lb
in
I
3
)
\newline
The weight of the piece of steel shown in the drawing is approximately
□
\square
□
lb. (Round to the nearest tenth as needed.)
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Unit
5
5
5
: Functions \& Linear Relationships
\newline
Homework
6
6
6
: Slope-Intercept Form
\newline
-page document! **
\newline
feach equation, then graph the line.
\newline
2
2
2
.
y
=
−
7
5
x
+
3
y=-\frac{7}{5} x+3
y
=
−
5
7
x
+
3
\newline
m
=
m=
m
=
\newline
\qquad
\newline
x
x
x
\newline
b
=
b=
b
=
\newline
\qquad
\newline
4
4
4
.
y
=
−
4
x
−
1
y=-4 x-1
y
=
−
4
x
−
1
\newline
m
=
m=
m
=
\newline
\qquad
\newline
b
=
b=
b
=
\newline
\qquad
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Home - Newton Municipal
\newline
(
1
1
1
) Love Thy Neigh bor
\newline
Untitled document - Googls
\newline
MAAP Practice Test
\newline
CHRINESIA THOMPSON
\newline
ByteLeam
\newline
35
35
35
. What is the simplified form of the polynomial expression shown?
\newline
−
3
x
2
(
x
−
y
2
)
−
(
y
3
−
5
)
−
3
y
2
(
x
2
−
4
y
)
+
4
x
3
-3x^{2}(x-y^{2})-(y^{3}-5)-3y^{2}(x^{2}-4y)+4x^{3}
−
3
x
2
(
x
−
y
2
)
−
(
y
3
−
5
)
−
3
y
2
(
x
2
−
4
y
)
+
4
x
3
\newline
Page
\newline
25
25
25
\newline
148
148
148
\newline
Fill in the blanks with the values.
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Which of the following is a rational number?
\newline
Choices:
\newline
(A)
π
\pi
π
\newline
(B)
4
7
\frac{4}{7}
7
4
\newline
(C)
10
\sqrt{10}
10
\newline
(D)
3
\sqrt{3}
3
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∫
4
x
cos
(
2
−
3
x
)
d
x
\int 4 x \cos (2-3 x) d x
∫
4
x
cos
(
2
−
3
x
)
d
x
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Approximating Irrational Numbers - Tutorial - Part
1
1
1
- Level H
\newline
et's try to find a rational approximation for
2
\sqrt{2}
2
.
\newline
hich interval on this number line contains
2
\sqrt{2}
2
? Click on the line cement betwcen the whole numbers to submit your answer.
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(b) Use integration by parts to evaluate
∫
0
π
2
x
⋅
cos
x
d
x
\int_0^{\frac{\pi}{2}} x \cdot \cos x \, dx
∫
0
2
π
x
⋅
cos
x
d
x
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∫
[
tan
x
]
d
x
\int[\sqrt{\tan x}] d x
∫
[
tan
x
]
d
x
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∫
tan
x
d
x
\int \sqrt{\tan x} d x
∫
tan
x
d
x
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1
1
1
.
∫
2
x
3
−
4
x
−
8
(
x
2
−
x
)
(
x
2
+
4
)
d
x
\int \frac{2 x^{3}-4 x-8}{\left(x^{2}-x\right)\left(x^{2}+4\right)} d x
∫
(
x
2
−
x
)
(
x
2
+
4
)
2
x
3
−
4
x
−
8
d
x
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18
18
18
.
∫
sin
2
x
sin
x
d
x
\int \frac{\sin 2 x}{\sin x} d x
∫
s
i
n
x
s
i
n
2
x
d
x
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11
11
11
.
∫
x
3
−
2
x
x
d
x
\int \frac{x^{3}-2 \sqrt{x}}{x} d x
∫
x
x
3
−
2
x
d
x
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∫
x
x
d
x
\int \frac{x}{x}dx
∫
x
x
d
x
\newline
∫
(
sin
x
+
sinh
x
)
d
x
\int(\sin x+\sinh x)dx
∫
(
sin
x
+
sinh
x
)
d
x
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11
11
11
.
∫
A
x
d
x
\int \frac{A}{x} d x
∫
x
A
d
x
\newline
13
13
13
.
∫
(
sin
x
+
sinh
x
)
d
x
\int(\sin x+\sinh x) d x
∫
(
sin
x
+
sinh
x
)
d
x
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6
6
6
.
∫
sec
t
(
sec
t
+
tan
t
)
d
t
\int \sec t(\sec t+\tan t) d t
∫
sec
t
(
sec
t
+
tan
t
)
d
t
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What could be the value of
x
x
x
in the following equation? Select all that apply.
\newline
x
2
=
1
36
x^2 = \frac{1}{36}
x
2
=
36
1
\newline
Multi-select Choices:
\newline
(A)
1
18
\frac{1}{18}
18
1
\newline
(B)
1
36
\sqrt{\frac{1}{36}}
36
1
\newline
(C)
−
1
18
-\frac{1}{18}
−
18
1
\newline
(D)
−
1
36
-\sqrt{\frac{1}{36}}
−
36
1
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RT
4
4
4
- Mathematical Knowledge
\newline
Evaluate
\newline
(
b
−
a
)
2
−
3
c
(
−
a
)
3
\frac{(b-a)^{2}-3c}{(-a)^{3}}
(
−
a
)
3
(
b
−
a
)
2
−
3
c
, when
\newline
a
=
4
a=4
a
=
4
,
b
=
5
b=5
b
=
5
, and
\newline
c
=
2
c=2
c
=
2
\newline
A
5
12
\frac{5}{12}
12
5
\newline
B
−
5
12
-\frac{5}{12}
−
12
5
\newline
C
5
64
\frac{5}{64}
64
5
\newline
D
−
5
64
\quad-\frac{5}{64}
−
64
5
\newline
Click the button or type the letter to the left of you
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RT
4
4
4
- Mathematical Knowledge
\newline
Evaluate
(
b
−
a
)
2
−
3
c
(
−
a
)
3
\frac{(b-a)^{2}-3 c}{(-a)^{3}}
(
−
a
)
3
(
b
−
a
)
2
−
3
c
, when
a
=
4
,
b
=
5
a=4, b=5
a
=
4
,
b
=
5
, and
c
=
2
c=2
c
=
2
\newline
A
5
/
12
\quad 5 / 12
5/12
\newline
B
−
5
/
12
-5 / 12
−
5/12
\newline
C
5
/
64
5 / 64
5/64
\newline
D
−
5
/
64
\quad-5 / 64
−
5/64
\newline
Click the button or type the letter to the left of you
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∫
5
−
x
2
d
x
x
4
\int \frac{\sqrt{5-x^{2}} d x}{x^{4}}
∫
x
4
5
−
x
2
d
x
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∫
(
3
x
+
4
)
cos
x
d
x
\int(3 x+4) \cos x d x
∫
(
3
x
+
4
)
cos
x
d
x
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∫
t
t
2
+
2
d
t
\int t \sqrt{t^{2}+2} d t
∫
t
t
2
+
2
d
t
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Evaluate the line integral, where
C
C
C
is the given curve.
\newline
∫
C
x
sin
(
y
)
d
s
,
C
\int_{C} x \sin (y) d s, C
∫
C
x
sin
(
y
)
d
s
,
C
is the line segment from
(
0
,
1
)
(0,1)
(
0
,
1
)
to
(
4
,
4
)
(4,4)
(
4
,
4
)
Get tutor help
5
5
5
)
∫
d
x
2
+
cos
x
\int \frac{d x}{2+\cos x}
∫
2
+
c
o
s
x
d
x
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∫
x
x
2
+
1
d
x
\int \frac{x}{\sqrt{x^{2}+1}} d x
∫
x
2
+
1
x
d
x
Get tutor help
Find the
8
th
8^{\text{th}}
8
th
term in the sequence
\newline
−
1
2
,
−
1
,
−
2
,
−
4
,
…
-\frac{1}{2},-1,-2,-4,\dots
−
2
1
,
−
1
,
−
2
,
−
4
,
…
\newline
Hint: Write a formula to help you.
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/
△
A
′
B
′
C
′
_{\triangle}A^{\prime}B^{\prime}C^{\prime}
△
A
′
B
′
C
′
is a dilation of /
△
A
B
C
_{\triangle}ABC
△
A
BC
. What is the scale factor?
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∫
x
2
−
4
2
x
d
x
\int \frac{x^{2}-4}{2 \sqrt{x}} d x
∫
2
x
x
2
−
4
d
x
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⇒
\Rightarrow
⇒
\newline
int ism
\newline
thent
\newline
Strte
\newline
ite:
\newline
Astor:
\newline
SixuE
\newline
F
\newline
Elsonter
\newline
c.
\newline
Conolitieth gemes
\newline
Test Taks
\newline
My IXL
\newline
Learning
\newline
Assessment
\newline
Analy
\newline
th grade > W.
6
6
6
Surface area of cones
5
5
5
E
6
6
6
\newline
Learn with an example
\newline
or
\newline
Watch a video
\newline
What is the surface area of this cone?
\newline
Use
π
≈
3.14
\pi \approx 3.14
π
≈
3.14
and round your answer to the nearest hundredth.
\newline
□
\square
□
square inches
\newline
Submit
\newline
Work it out
\newline
Not feeling ready yet? These can help:
\newline
Area of circles
\newline
Lesson: Surface area
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Question
8
8
8
\newline
*
1
1
1
point
\newline
The point
A
(
3
,
5
)
A(3,5)
A
(
3
,
5
)
is mapped onto
A
′
(
3
,
−
5
)
A^{\prime}(3,-5)
A
′
(
3
,
−
5
)
by a transformation represented by the matrix
T
\mathrm{T}
T
. The matrix
T
\mathrm{T}
T
could be
\newline
(
1
0
1
1
)
(
1
−
1
0
1
)
\left(\begin{array}{ll} 1 & 0 \\ 1 & 1 \end{array}\right) \quad\left(\begin{array}{cc} 1 & -1 \\ 0 & 1 \end{array}\right)
(
1
1
0
1
)
(
1
0
−
1
1
)
\newline
A
\newline
B
\newline
(
−
1
0
0
−
1
)
(
1
0
0
−
1
)
\left(\begin{array}{rr} -1 & 0 \\ 0 & -1 \end{array}\right) \quad\left(\begin{array}{rr} 1 & 0 \\ 0 & -1 \end{array}\right)
(
−
1
0
0
−
1
)
(
1
0
0
−
1
)
\newline
C
\newline
D
Get tutor help
Substitution by parts: blem
10
10
10
\newline
t)
\newline
ate the indefinite integral.
\newline
)
\newline
x
sin
2
(
5
x
)
d
x
=
□
+
C
x \sin ^{2}(5 x) d x=\square+C
x
sin
2
(
5
x
)
d
x
=
□
+
C
.
\newline
Hint: Integrate by parts with
u
=
x
u=x
u
=
x
.
\newline
gauss.vaniercollege.qc.ca
\newline
gauss.vaniercollege.qc.ca
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Use the graph of the function to complete the table.
\newline
\begin{tabular}{|c|c|}
\newline
\hline input & output \\
\newline
\hline
−
9
-9
−
9
&
□
\square
□
\\
\newline
\hline
−
5
-5
−
5
&
□
\square
□
\\
\newline
\hline
−
3
-3
−
3
&
−
9
-9
−
9
\\
\newline
\hline
\newline
\end{tabular}
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∫
1
x
3
ln
x
d
x
\int \frac{1}{x^{3}}\ln x \, dx
∫
x
3
1
ln
x
d
x
Get tutor help
Question
6
6
6
\newline
*
1
1
1
point
\newline
Δ
L
M
N
\Delta \mathrm{LMN}
Δ
LMN
, below, is rotated anti-clockwise about
L
\mathrm{L}
L
through
9
0
∘
90^{\circ}
9
0
∘
. Which of the following is its likely image?
\qquad
\newline
A
\newline
A
\newline
\qquad
\newline
C
\newline
]
′
4
M
\sqrt{]^{\prime} 4^{M}}
]
′
4
M
\newline
D
Get tutor help
∫
(
8
x
+
8
x
)
d
x
\int\left(\frac{8}{\sqrt{x}}+8 \sqrt{x}\right) d x
∫
(
x
8
+
8
x
)
d
x
Get tutor help
https://www-awa.aleks.com/alekscgi///lsl.exe/
\newline
Unproctored Placement Assessment Question
9
9
9
\newline
Use the distributive property to rem
\newline
2
a
5
(
10
a
+
4
a
4
)
2 a^{5}\left(10 a+4 a^{4}\right)
2
a
5
(
10
a
+
4
a
4
)
\newline
Simplify your answer as much as po
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∫
Γ
(
e
2
2
⋅
(
2
2
+
1
)
)
d
z
\int_{\Gamma}\left(\frac{e^{2}}{2\cdot(2^{2}+1)}\right)dz
∫
Γ
(
2
⋅
(
2
2
+
1
)
e
2
)
d
z
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∫
Γ
e
2
z
⋅
(
2
2
+
1
)
d
z
\int_{\Gamma} \frac{e^{2}}{z \cdot\left(2^{2}+1\right)} d z
∫
Γ
z
⋅
(
2
2
+
1
)
e
2
d
z
Get tutor help
Part A
\newline
Indicate the order of reaction consistent with each observation.
\newline
Drag the appropriate items to their respective bins.
\newline
Zero order
\newline
A plot of the concentration of the reactant versus time yields a straight line.
\newline
Course Home
\newline
The
Blank
\text{Blank}
Blank
rate of
\newline
You can determi
\newline
A
(
′
′
)
A^{('')}
A
(
′′
)
\newline
E
^
\hat{E}
E
^
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ext{ extbackslash int extbackslash sqrt extbackslash left(}x^{
2
2
2
}+
1
1
1
ext{ extbackslash right)dx not using tangent}
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∫
x
2
+
1
d
x
\int \sqrt{x^{2}+1} d x
∫
x
2
+
1
d
x
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∫
(
x
−
3
e
3
x
)
d
x
\int\left(x-3 e^{3 x}\right) d x
∫
(
x
−
3
e
3
x
)
d
x
Get tutor help
Perform the division.
\newline
(
10
x
15
−
15
x
12
+
25
x
9
−
45
x
6
)
÷
(
5
x
18
)
(
10
x
15
−
15
x
12
+
25
x
9
−
45
x
6
)
÷
(
5
x
18
)
=
\begin{array}{l} \left(10 x^{15}-15 x^{12}+25 x^{9}-45 x^{6}\right) \div\left(5 x^{18}\right) \\ \left(10 x^{15}-15 x^{12}+25 x^{9}-45 x^{6}\right) \div\left(5 x^{18}\right)= \end{array}
(
10
x
15
−
15
x
12
+
25
x
9
−
45
x
6
)
÷
(
5
x
18
)
(
10
x
15
−
15
x
12
+
25
x
9
−
45
x
6
)
÷
(
5
x
18
)
=
\newline
□
\square
□
(Simplify your answer. Use integers or fractions for any numbers in the expression.)
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