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sqrts+7=6+4sqrts What is the solution to the given equation?

s+7=6+4s \sqrt{s}+7=6+4 \sqrt{s} \newlineWhat is the solution to the given equation?

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Full solution

Q. s+7=6+4s \sqrt{s}+7=6+4 \sqrt{s} \newlineWhat is the solution to the given equation?
  1. Isolate square root term: First, isolate the square root term on one side of the equation.\newlines+7−7=6+4s−7\sqrt{s} + 7 - 7 = 6 + 4\sqrt{s} - 7\newlines=4s−1\sqrt{s} = 4\sqrt{s} - 1
  2. Move terms with s\sqrt{s}: Next, move all terms containing s\sqrt{s} to one side of the equation.\newlines−4s=−1\sqrt{s} - 4\sqrt{s} = -1\newline−3s=−1-3\sqrt{s} = -1
  3. Divide by −3-3: Now, divide both sides by −3-3 to solve for s\sqrt{s}.s=−1−3\sqrt{s} = \frac{-1}{-3}s=13\sqrt{s} = \frac{1}{3}
  4. Square both sides: Square both sides to solve for ss.(s)2=(13)2(\sqrt{s})^2 = (\frac{1}{3})^2s=19s = \frac{1}{9}

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