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Solve using the quadratic formula.\newline9v2+8v6=09v^2 + 8v - 6 = 0\newlineWrite your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.\newlinev=v = _____ or v=v = _____

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Q. Solve using the quadratic formula.\newline9v2+8v6=09v^2 + 8v - 6 = 0\newlineWrite your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.\newlinev=v = _____ or v=v = _____
  1. Identify values: Identify the values of aa, bb, and cc in the quadratic equation 9v2+8v6=09v^2 + 8v - 6 = 0. Compare 9v2+8v6=09v^2 + 8v - 6 = 0 with the standard form ax2+bx+c=0ax^2 + bx + c = 0. a=9a = 9 b=8b = 8 c=6c = -6
  2. Substitute values: Substitute the values of aa, bb, and cc into the quadratic formula v=b±b24ac2av = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}. Substitute a=9a = 9, b=8b = 8, and c=6c = -6 into the formula. v=(8)±(8)249(6)29v = \frac{-(8) \pm \sqrt{(8)^2 - 4\cdot9\cdot(-6)}}{2\cdot9}
  3. Simplify expression: Simplify the expression under the square root and calculate its value.\newline(8)249(6)\sqrt{(8)^2 - 4\cdot 9\cdot (-6)}\newline= 64+216\sqrt{64 + 216}\newline= 280\sqrt{280}
  4. Simplify formula: Simplify the quadratic formula with the calculated square root value.\newlinev=8±28018v = \frac{-8 \pm \sqrt{280}}{18}\newlineSince 280\sqrt{280} simplifies to 4×70\sqrt{4\times70} which is 2×702\times\sqrt{70}, we can further simplify the expression.\newlinev=8±2×7018v = \frac{-8 \pm 2\times\sqrt{70}}{18}
  5. Calculate solutions: Simplify the expression by dividing all terms by 22.\newlinev=4±709v = \frac{-4 \pm \sqrt{70}}{9}\newlineNow we have two possible solutions for vv.
  6. Calculate solutions: Simplify the expression by dividing all terms by 22.\newlinev=4±709v = \frac{-4 \pm \sqrt{70}}{9}\newlineNow we have two possible solutions for vv.Calculate the two possible solutions for vv and round them to the nearest hundredth if necessary.\newlineFirst solution:\newlinev=4+709v = \frac{-4 + \sqrt{70}}{9}\newlinev4+8.379v \approx \frac{-4 + 8.37}{9}\newlinev4.379v \approx \frac{4.37}{9}\newlinev0.49v \approx 0.49\newlineSecond solution:\newlinev=4709v = \frac{-4 - \sqrt{70}}{9}\newlinev48.379v \approx \frac{-4 - 8.37}{9}\newlinev12.379v \approx \frac{-12.37}{9}\newlinevv00

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