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Solve using augmented matrices.\newliney=10y = 10\newline9x+10y=109x + 10y = 10\newline(_____, _____)

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Q. Solve using augmented matrices.\newliney=10y = 10\newline9x+10y=109x + 10y = 10\newline(_____, _____)
  1. Write Equations as Matrix: Write the system of equations as an augmented matrix. [1010 91010]\left[\begin{array}{cc|c} 1 & 0 & 10 \ 9 & 10 & 10 \end{array}\right]
  2. Modify Second Equation: Since the first equation is already solved for yy, we can use it to modify the second equation.\newlineSubtract 1010 times the first row from the second row to eliminate the yy-term.\newlineNew second row: [9,10,10]10×[1,0,10]=[9,10,10][10,0,100]=[1,10,90][9, 10, 10] - 10\times[1, 0, 10] = [9, 10, 10] - [10, 0, 100] = [-1, 10, -90]
  3. Replace Second Row: Replace the second row with the new values.\newlineThe augmented matrix now looks like this:\newline\left[\begin{array}{ccc}\(\newline1 & 0 & 10 (\newline\)-1 & 10 & -90\newline\end{array}\right]\)
  4. Add First Row: Add the first row to the second row to get the xx-term alone.\newlineNew second row: [\(-1, 1010, 90-90\] + [\(1, 00, 1010\] = [\(0, 1010, 80-80\]
  5. Divide Second Row: Divide the second row by 1010 to solve for xx.\newline New second row: [0,10,80]/10=[0,1,8][0, 10, -80] / 10 = [0, 1, -8]
  6. Final Solution: Now we have the second equation in the form of x=8x = -8. So the solution to the system is (x,y)=(8,10)(x, y) = (-8, 10).