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Solve for pp in terms of qq, rr, ss, and tt. \newlinesq=−tprsq = -tpr \newlinep=p = ______

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Full solution

Q. Solve for pp in terms of qq, rr, ss, and tt. \newlinesq=−tprsq = -tpr \newlinep=p = ______
  1. Get pp alone: We got sq=−tprsq = -tpr. To get pp alone, we should divide both sides by −tr-tr.\newlineSo, sq(−tr)=−tpr(−tr)\frac{sq}{(-tr)} = \frac{-tpr}{(-tr)}.
  2. Divide both sides: After dividing, we get p=sq−trp = \frac{sq}{-tr}. But wait, there's a mistake here. We need to fix it.

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