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Solve for nn.\newline10+3n=6n2010 + 3n = 6n - 20\newlinen=n = __

Full solution

Q. Solve for nn.\newline10+3n=6n2010 + 3n = 6n - 20\newlinen=n = __
  1. Get all terms together: First, let's get all the nn terms on one side by subtracting 3n3n from both sides: 10+3n3n=6n203n10 + 3n - 3n = 6n - 20 - 3n.
  2. Isolate the n term: Now we have 10=3n2010 = 3n - 20. Next, we'll add 2020 to both sides to isolate the n term: 10+20=3n20+2010 + 20 = 3n - 20 + 20.
  3. Divide by 33: After adding, we get 30=3n30 = 3n. Now, we divide both sides by 33 to solve for nn: 303=3n3\frac{30}{3} = \frac{3n}{3}.
  4. Find the value of \newline: Finally, we find that \newline = \newline. So, \newline equals \newline.

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