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Solve for cc.\newline−17c=−19c−10-17c = -19c - 10\newlinec=c = ____

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Full solution

Q. Solve for cc.\newline−17c=−19c−10-17c = -19c - 10\newlinec=c = ____
  1. Divide by 22: Now, we divide both sides by 22 to solve for cc.2c2=−102\frac{2c}{2} = \frac{-10}{2}c=−5c = -5

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