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Solve for b. 49=16+(3)/(7)b Answer: b=

Solve for b b .\newline49=16+37b 49=16+\frac{3}{7} b \newlineAnswer: b= b=

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Full solution

Q. Solve for b b .\newline49=16+37b 49=16+\frac{3}{7} b \newlineAnswer: b= b=
  1. Subtract to isolate bb: We have the equation 49=16+(37)b49 = 16 + \left(\frac{3}{7}\right)b. To isolate bb, we should first subtract 1616 from both sides of the equation.\newlineCalculation: 49−16=16+(37)b−1649 - 16 = 16 + \left(\frac{3}{7}\right)b - 16\newline33=(37)b33 = \left(\frac{3}{7}\right)b
  2. Multiply by reciprocal to solve: Now we have 33=(37)b33 = \left(\frac{3}{7}\right)b. To solve for bb, we need to multiply both sides by the reciprocal of (37)\left(\frac{3}{7}\right), which is (73)\left(\frac{7}{3}\right).\newlineCalculation: 33×(73)=(37)b×(73)33 \times \left(\frac{7}{3}\right) = \left(\frac{3}{7}\right)b \times \left(\frac{7}{3}\right)\newline77=b77 = b

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