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Let’s check out your problem:
Solve for all values of
x
x
x
.
x
−
2
x
−
3
=
2
x - \frac{2}{x - 3} = 2
x
−
x
−
3
2
=
2
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Math Problems
Algebra 2
Factor sums and differences of cubes
Full solution
Q.
Solve for all values of
x
x
x
.
x
−
2
x
−
3
=
2
x - \frac{2}{x - 3} = 2
x
−
x
−
3
2
=
2
Multiply and Simplify:
First, let's get rid of the fraction by multiplying everything by
(
x
−
3
)
(x - 3)
(
x
−
3
)
.
(
x
−
2
x
−
3
)
(
x
−
3
)
=
2
(
x
−
3
)
(x - \frac{2}{x - 3})(x - 3) = 2(x - 3)
(
x
−
x
−
3
2
)
(
x
−
3
)
=
2
(
x
−
3
)
Distribute and Expand:
Now distribute
x
−
3
x - 3
x
−
3
on the left side and simplify the right side.
x
(
x
−
3
)
−
2
=
2
x
−
6
x(x - 3) - 2 = 2x - 6
x
(
x
−
3
)
−
2
=
2
x
−
6
Subtract and Simplify:
Expand the left side of the equation.
x
2
−
3
x
−
2
=
2
x
−
6
x^2 - 3x - 2 = 2x - 6
x
2
−
3
x
−
2
=
2
x
−
6
Add and Set to Zero:
Subtract
2
x
2x
2
x
from both sides to get a quadratic equation.
\newline
x
2
−
5
x
−
2
=
−
6
x^2 - 5x - 2 = -6
x
2
−
5
x
−
2
=
−
6
Factor the Equation:
Add
6
6
6
to both sides to set the quadratic equation to zero.
\newline
x
2
−
5
x
+
4
=
0
x^2 - 5x + 4 = 0
x
2
−
5
x
+
4
=
0
Set Factors Equal:
Factor the quadratic equation.
\newline
(
x
−
4
)
(
x
−
1
)
=
0
(x - 4)(x - 1) = 0
(
x
−
4
)
(
x
−
1
)
=
0
Solve for x:
Set each factor equal to zero and solve for x.
\newline
x
−
4
=
0
x - 4 = 0
x
−
4
=
0
or
x
−
1
=
0
x - 1 = 0
x
−
1
=
0
Solve for x:
Solve the first equation for x.
\newline
x
=
4
x = 4
x
=
4
Solve for x:
Solve the first equation for x.
\newline
x
=
4
x = 4
x
=
4
Solve the second equation for x.
\newline
x
=
1
x = 1
x
=
1
More problems from Factor sums and differences of cubes
Question
Factor out the greatest common factor. If the greatest common factor is
1
1
1
, just retype the polynomial.
\newline
4
x
3
−
6
x
2
4x^3 - 6x^2
4
x
3
−
6
x
2
\newline
______
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Posted 2 months ago
Question
Factor
x
4
+
8
x
2
+
16
x^4 + 8x^2 + 16
x
4
+
8
x
2
+
16
completely.
\newline
All factors in your answer should have integer coefficients.
\newline
______
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Posted 2 months ago
Question
Find the binomial that completes the factorization.
\newline
t
3
+
u
3
=
(
‾
)
(
t
2
−
t
u
+
u
2
)
t^3 + u^3 = (\underline{\hspace{1cm}}) (t^2 - tu + u^2)
t
3
+
u
3
=
(
)
(
t
2
−
t
u
+
u
2
)
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Posted 2 months ago
Question
Factor.
\newline
g
2
−
11
g
+
18
g^2 - 11g + 18
g
2
−
11
g
+
18
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Posted 2 months ago
Question
Factor.
\newline
2
y
3
−
y
2
+
16
y
−
8
2y^3 - y^2 + 16y - 8
2
y
3
−
y
2
+
16
y
−
8
\newline
______
\newline
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Posted 2 months ago
Question
Factor.
\newline
2
x
8
+
7
x
2
2x^8 + 7x^2
2
x
8
+
7
x
2
\newline
______
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Posted 3 months ago
Question
Factor.
\newline
9
y
12
+
4
y
5
−
y
2
9y^{12} + 4y^5 - y^2
9
y
12
+
4
y
5
−
y
2
\newline
______
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Posted 3 months ago
Question
Factor.
\newline
6
a
4
+
3
a
3
−
a
+
2
6a^4 + 3a^3 - a + 2
6
a
4
+
3
a
3
−
a
+
2
\newline
_____
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Posted 3 months ago
Question
Factor.
\newline
4
c
7
−
2
c
5
+
c
2
−
5
4c^7 - 2c^5 + c^2 - 5
4
c
7
−
2
c
5
+
c
2
−
5
\newline
_____
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Posted 3 months ago
Question
Factor.
\newline
7
m
9
+
2
m
6
−
m
3
+
4
m
−
10
7m^9 + 2m^6 - m^3 + 4m - 10
7
m
9
+
2
m
6
−
m
3
+
4
m
−
10
\newline
_____
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Posted 3 months ago