Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Solve for all real values of 
x.

x^(2)-9=0
Answer: 
x=

Solve for all real values of x x .\newlinex29=0 x^{2}-9=0 \newlineAnswer: x= x= \newline

Full solution

Q. Solve for all real values of x x .\newlinex29=0 x^{2}-9=0 \newlineAnswer: x= x= \newline
  1. Set up the equation: Set up the equation.\newlineWe have the equation x29=0x^{2} - 9 = 0.\newlineTo solve for xx, we need to find the values that make this equation true.
  2. Factor the left side: Factor the left side of the equation.\newlineThe left side of the equation is a difference of squares, which can be factored into (x+3)(x3)(x + 3)(x - 3).\newlineSo, x29=(x+3)(x3)x^{2} - 9 = (x + 3)(x - 3).
  3. Set each factor equal: Set each factor equal to zero.\newlineSince the product of the factors is zero, we can set each factor equal to zero and solve for xx.\newlinex+3=0x + 3 = 0 or x3=0x - 3 = 0.
  4. Solve each equation for xx: Solve each equation for xx. For the first equation, x+3=0x + 3 = 0, we subtract 33 from both sides to get x=3x = -3. For the second equation, x3=0x - 3 = 0, we add 33 to both sides to get x=3x = 3.

More problems from Solve a quadratic equation using square roots