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Solve for all real values of
x.

x^(2)-1=0
Answer:
x=
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sqrt+-

Solve for all real values of $x$ . $\newline$ $x^{2}-1=0$ $\newline$ Answer: $x=$

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Solve a quadratic equation using square roots

Full solution

Q. Solve for all real values of

x

.

\newline

x^{2}-1=0

\newline

Answer:

x=

Set up the equation: Set up the equation. $\newline$ We have the equation $x^{2} - 1 = 0$ . $\newline$ To solve for $x$ , we need to find the values that make this equation true.
Factor the left side: Factor the left side of the equation. $\newline$ The left side of the equation is a difference of squares, which can be factored into $(x + 1)(x - 1)$ . $\newline$ So, $x^{2} - 1 = (x + 1)(x - 1)$ .
Set each factor equal: Set each factor equal to zero. $\newline$ Since the product of the factors is zero, we can set each factor equal to zero to find the values of $x$ . $\newline$ $x + 1 = 0$ or $x - 1 = 0$
Solve each equation for $x$ : Solve each equation for $x$ . $\newline$ For the first equation, $x + 1 = 0$ , we subtract $1$ from both sides to get $x = -1$ . $\newline$ For the second equation, $x - 1 = 0$ , we add $1$ to both sides to get $x = 1$ .

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