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Solve for all real values of 
x.

x^(2)-1=0
Answer: 
x=

Solve for all real values of x x .\newlinex21=0 x^{2}-1=0 \newlineAnswer: x= x= \newline

Full solution

Q. Solve for all real values of x x .\newlinex21=0 x^{2}-1=0 \newlineAnswer: x= x= \newline
  1. Set up equation: Set up the equation to solve for xx. We have the equation x21=0x^{2} - 1 = 0. To find the values of xx, we need to solve this equation.
  2. Factor left side: Factor the left side of the equation.\newlineThe left side of the equation is a difference of squares, which can be factored as (x+1)(x1)=0(x + 1)(x - 1) = 0.
  3. Set factors equal: Set each factor equal to zero and solve for xx.\newlineSince the product of the factors is zero, at least one of the factors must be zero.\newlineSo we set each factor equal to zero and solve for xx:\newlinex+1=0x + 1 = 0 or x1=0x - 1 = 0.
  4. Solve first equation: Solve the first equation x+1=0x + 1 = 0.\newlineSubtract 11 from both sides to isolate xx:\newlinex=1x = -1.
  5. Solve second equation: Solve the second equation x1=0x - 1 = 0. Add 11 to both sides to isolate xx: x=1x = 1.

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