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Let’s check out your problem:
Solve
a
x
+
a
+
b
x
−
b
=
a
+
b
x
+
c
\frac{a}{x+a}+\frac{b}{x-b}=\frac{a+b}{x+c}
x
+
a
a
+
x
−
b
b
=
x
+
c
a
+
b
for
x
x
x
View step-by-step help
Home
Math Problems
Algebra 2
Write a quadratic function from its x-intercepts and another point
Full solution
Q.
Solve
a
x
+
a
+
b
x
−
b
=
a
+
b
x
+
c
\frac{a}{x+a}+\frac{b}{x-b}=\frac{a+b}{x+c}
x
+
a
a
+
x
−
b
b
=
x
+
c
a
+
b
for
x
x
x
Rewrite with common denominator:
Now, rewrite each fraction with the common denominator:
a
(
x
−
b
)
(
x
+
a
)
(
x
−
b
)
+
b
(
x
+
a
)
(
x
+
a
)
(
x
−
b
)
=
a
+
b
x
+
c
\frac{a(x-b)}{(x+a)(x-b)} + \frac{b(x+a)}{(x+a)(x-b)} = \frac{a+b}{x+c}
(
x
+
a
)
(
x
−
b
)
a
(
x
−
b
)
+
(
x
+
a
)
(
x
−
b
)
b
(
x
+
a
)
=
x
+
c
a
+
b
.
Combine fractions:
Combine the fractions on the left side:
(
a
x
−
a
b
)
+
(
b
x
+
a
b
)
(
x
+
a
)
(
x
−
b
)
=
a
+
b
x
+
c
\frac{(ax - ab) + (bx + ab)}{(x+a)(x-b)} = \frac{a+b}{x+c}
(
x
+
a
)
(
x
−
b
)
(
a
x
−
ab
)
+
(
b
x
+
ab
)
=
x
+
c
a
+
b
.
Simplify numerator:
Simplify the numerator on the left side:
(
a
x
+
b
x
)
/
(
x
+
a
)
(
x
−
b
)
=
(
a
+
b
)
/
(
x
+
c
)
(ax + bx)/(x+a)(x-b) = (a+b)/(x+c)
(
a
x
+
b
x
)
/
(
x
+
a
)
(
x
−
b
)
=
(
a
+
b
)
/
(
x
+
c
)
.
Combine like terms:
Combine like terms in the numerator:
(
a
+
b
)
x
/
(
x
+
a
)
(
x
−
b
)
=
(
a
+
b
)
/
(
x
+
c
)
(a+b)x/(x+a)(x-b) = (a+b)/(x+c)
(
a
+
b
)
x
/
(
x
+
a
)
(
x
−
b
)
=
(
a
+
b
)
/
(
x
+
c
)
.
Cancel out common factor:
Since
(
a
+
b
)
(a+b)
(
a
+
b
)
appears in both numerators, we can cancel it out, assuming
a
+
b
≠
0
a+b \neq 0
a
+
b
=
0
:
x
(
x
+
a
)
(
x
−
b
)
=
1
(
x
+
c
)
.
\frac{x}{(x+a)(x-b)} = \frac{1}{(x+c)}.
(
x
+
a
)
(
x
−
b
)
x
=
(
x
+
c
)
1
.
Cross-multiply:
Cross-multiply to get rid of the fractions:
x
(
x
+
c
)
=
(
x
+
a
)
(
x
−
b
)
x(x+c) = (x+a)(x-b)
x
(
x
+
c
)
=
(
x
+
a
)
(
x
−
b
)
.
Expand both sides:
Expand both sides:
x
2
+
c
x
=
x
2
+
a
x
−
b
x
−
a
b
x^2 + cx = x^2 + ax - bx - ab
x
2
+
c
x
=
x
2
+
a
x
−
b
x
−
ab
.
Subtract
x
2
x^2
x
2
:
Subtract
x
2
x^2
x
2
from both sides to simplify:
c
x
=
a
x
−
b
x
−
a
b
cx = ax - bx - ab
c
x
=
a
x
−
b
x
−
ab
.
Combine like terms:
Combine like terms:
c
x
=
(
a
−
b
)
x
−
a
b
cx = (a - b)x - ab
c
x
=
(
a
−
b
)
x
−
ab
.
Subtract
(
a
−
b
)
x
(a - b)x
(
a
−
b
)
x
:
Subtract
(
a
−
b
)
x
(a - b)x
(
a
−
b
)
x
from both sides:
\newline
c
x
−
(
a
−
b
)
x
=
−
a
b
cx - (a - b)x = -ab
c
x
−
(
a
−
b
)
x
=
−
ab
.
Factor out
x
x
x
:
Factor out
x
x
x
on the left side:
\newline
x
(
c
−
a
+
b
)
=
−
a
b
x(c - a + b) = -ab
x
(
c
−
a
+
b
)
=
−
ab
.
Divide to solve for
x
x
x
:
Divide both sides by
(
c
−
a
+
b
)
(c - a + b)
(
c
−
a
+
b
)
to solve for
x
x
x
:
x
=
−
a
b
(
c
−
a
+
b
)
.
x = \frac{-ab}{(c - a + b)}.
x
=
(
c
−
a
+
b
)
−
ab
.
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Question
Solve by completing the square.
\newline
m
2
−
10
m
−
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=
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m^2 - 10m - 29 = 0
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2
−
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m
−
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\newline
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\newline
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2
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f
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\newline
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2
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a(x–h)^2+k
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y
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x
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4
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y
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\newline
{
y
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y
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\newline
{
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{
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all real numbers
\text{all real numbers}
all real numbers
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0
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(
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y
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(
x
–
p
)
(
x
–
q
)
y = a(x – p)(x – q)
y
=
a
(
x
–
p
)
(
x
–
q
)
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a
a
a
,
p
p
p
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q
q
q
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\newline
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h
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39
h
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\newline
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Write a quadratic function with zeros
−
9
-9
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9
and
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7
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−
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.
\newline
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x
x
x
and in standard form with a leading coefficient of
1
1
1
.
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(
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)
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_
_
_
_
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(
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Question
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y
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‾
\underline{\hspace{3cm}}
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Question
Find
g
(
x
)
g(x)
g
(
x
)
, where
g
(
x
)
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g
(
x
)
is the translation
8
8
8
units up of
f
(
x
)
=
x
2
f(x) = x^2
f
(
x
)
=
x
2
.
\newline
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a
(
x
–
h
)
2
+
k
a(x – h)^2 + k
a
(
x
–
h
)
2
+
k
, where
a
a
a
,
h
h
h
, and
k
k
k
are integers.
\newline
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(
x
)
=
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g
(
x
)
=
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x
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