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sin(xy)=y^(2)+cos(y)

sin(xy)=y2+cos(y) \sin (x y)=y^{2}+\cos (y)

Full solution

Q. sin(xy)=y2+cos(y) \sin (x y)=y^{2}+\cos (y)
  1. Identify function: Identify the function to differentiate and apply implicit differentiation. ddx[sin(xy)]=ddx[y2]+ddx[cos(y)]\frac{d}{dx}[\sin(xy)] = \frac{d}{dx}[y^{2}] + \frac{d}{dx}[\cos(y)]
  2. Apply implicit differentiation: Differentiate sin(xy)\sin(xy) using the chain rule and product rule.\newlineddx[sin(xy)]=cos(xy)(y+xdydx)\frac{d}{dx}[\sin(xy)] = \cos(xy) \cdot (y + x \cdot \frac{dy}{dx})
  3. Differentiate sin(xy)\sin(xy): Differentiate y2y^2 with respect to xx, treating yy as a function of xx.ddx[y2]=2ydydx\frac{d}{dx}[y^2] = 2y \cdot \frac{dy}{dx}
  4. Differentiate y2y^2: Differentiate cos(y)\cos(y) with respect to xx, treating yy as a function of xx.\newlineddx[cos(y)]=sin(y)dydx\frac{d}{dx}[\cos(y)] = -\sin(y) \cdot \frac{dy}{dx}
  5. Differentiate cos(y)\cos(y): Combine the derivatives to form an equation.\newlinecos(xy)(y+xdydx)=2ydydxsin(y)dydx\cos(xy) \cdot (y + x \frac{dy}{dx}) = 2y \frac{dy}{dx} - \sin(y) \frac{dy}{dx}
  6. Combine derivatives: Solve for dydx\frac{dy}{dx}.dydx(cos(xy)x2y+sin(y))=cos(xy)y\frac{dy}{dx} \cdot (\cos(xy) \cdot x - 2y + \sin(y)) = -\cos(xy) \cdot ydydx=cos(xy)ycos(xy)x2y+sin(y)\frac{dy}{dx} = \frac{-\cos(xy) \cdot y}{\cos(xy) \cdot x - 2y + \sin(y)}

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