Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Select the outlier in the data set.\newline58,68,74,78,79,82,86,76158, 68, 74, 78, 79, 82, 86, 761

Full solution

Q. Select the outlier in the data set.\newline58,68,74,78,79,82,86,76158, 68, 74, 78, 79, 82, 86, 761
  1. List Data Set: List the data set in ascending order.\newlineData set: 58,68,74,78,79,82,86,76158, 68, 74, 78, 79, 82, 86, 761.
  2. Calculate IQR: Calculate the interquartile range (IQR).\newlineFirst, find the median (Q22). The median of 58,68,74,78,79,82,86,76158, 68, 74, 78, 79, 82, 86, 761 is the average of 7878 and 7979.\newlineMedian (Q22) = (78+79)/2=78.5(78 + 79) / 2 = 78.5\newlineNext, find Q11 and Q33.\newlineLower half: 58,68,74,7858, 68, 74, 78\newlineUpper half: 79,82,86,76179, 82, 86, 761\newlineMedian of lower half (Q11): (68+74)/2=71(68 + 74) / 2 = 71\newlineMedian of upper half (Q33): (82+86)/2=84(82 + 86) / 2 = 84\newlineIQR = Q3Q1=8471=13Q3 - Q1 = 84 - 71 = 13
  3. Determine Outlier Threshold: Determine the outlier threshold.\newlineLower bound = Q11.5×IQR=711.5×13=51.5Q1 - 1.5 \times IQR = 71 - 1.5 \times 13 = 51.5\newlineUpper bound = Q3+1.5×IQR=84+1.5×13=103.5Q3 + 1.5 \times IQR = 84 + 1.5 \times 13 = 103.5\newlineValues outside these bounds are considered outliers.
  4. Identify Outlier: Identify the outlier.\newlineThe value 761761 is way above the upper bound of 103.5103.5, making it the outlier.

More problems from Calculate quartiles and interquartile range