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Select the outlier in the data set.\newline4,55,57,58,61,63,68,72,824, 55, 57, 58, 61, 63, 68, 72, 82\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline4,55,57,58,61,63,68,72,824, 55, 57, 58, 61, 63, 68, 72, 82\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Arrange Data Set: Arrange the data set in ascending order and identify any value that is significantly different from the others.\newlineThe data set in ascending order is: 4,55,57,58,61,63,68,72,824, 55, 57, 58, 61, 63, 68, 72, 82.\newlineThe value 44 stands out as being significantly lower than the rest of the values.
  2. Calculate IQR: Calculate the interquartile range (IQR) to determine the outlier threshold.\newlineFirst, find the first quartile (Q1Q_1) and the third quartile (Q3Q_3) of the data set.\newlineQ1Q_1 is the median of the first half: (55+57)/2=56(55 + 57) / 2 = 56.\newlineQ3Q_3 is the median of the second half: (68+72)/2=70(68 + 72) / 2 = 70.\newlineIQR=Q3Q1=7056=14IQR = Q_3 - Q_1 = 70 - 56 = 14.
  3. Calculate Outlier Boundaries: Calculate the outlier boundaries using the IQR.\newlineLower boundary = Q11.5×IQR=561.5×14=5621=35Q1 - 1.5 \times IQR = 56 - 1.5 \times 14 = 56 - 21 = 35.\newlineUpper boundary = Q3+1.5×IQR=70+1.5×14=70+21=91Q3 + 1.5 \times IQR = 70 + 1.5 \times 14 = 70 + 21 = 91.\newlineAny value below 3535 or above 9191 is considered an outlier.
  4. Identify Outlier: Identify the outlier based on the calculated boundaries.\newlineThe value 44 is below the lower boundary of 3535, so it is an outlier.
  5. Effect on Mean: Determine the effect on the mean if the outlier is removed.\newlineRemoving a value that is lower than the mean will result in an increase in the mean.\newlineSince 44 is lower than the rest of the values, removing it will increase the mean.

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