Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Select the outlier in the data set. \newline36,46,54,60,62,74,88,94,37136, 46, 54, 60, 62, 74, 88, 94, 371

Full solution

Q. Select the outlier in the data set. \newline36,46,54,60,62,74,88,94,37136, 46, 54, 60, 62, 74, 88, 94, 371
  1. Arrange Data Set: Arrange the data set in ascending order.\newlineThe data set is already in ascending order: 36,46,54,60,62,74,88,94,37136, 46, 54, 60, 62, 74, 88, 94, 371.
  2. Calculate Quartiles: Calculate the first quartile (Q1Q_1), the median (Q2Q_2), and the third quartile (Q3Q_3) of the data set.\newlineTo find Q1Q_1, we take the median of the first half of the data set (excluding the median if there is an odd number of data points). For Q3Q_3, we take the median of the second half of the data set.\newlineFirst half (for Q1Q_1): 36,46,54,6036, 46, 54, 60\newlineSecond half (for Q3Q_3): 62,74,88,9462, 74, 88, 94\newlineMedian of first half (Q1Q_1): Q2Q_200\newlineMedian of second half (Q3Q_3): Q2Q_222
  3. Calculate IQR: Calculate the interquartile range (IQR). IQR=Q3Q1=8150=31IQR = Q3 - Q1 = 81 - 50 = 31
  4. Determine Bounds: Determine the lower and upper bounds for potential outliers.\newlineLower bound = Q11.5×IQR=501.5×31=5046.5=3.5Q1 - 1.5 \times IQR = 50 - 1.5 \times 31 = 50 - 46.5 = 3.5\newlineUpper bound = Q3+1.5×IQR=81+1.5×31=81+46.5=127.5Q3 + 1.5 \times IQR = 81 + 1.5 \times 31 = 81 + 46.5 = 127.5
  5. Identify Outliers: Identify any data points that fall outside the lower and upper bounds. The value 371371 is well above the upper bound of 127.5127.5, so it is considered an outlier.

More problems from Calculate quartiles and interquartile range