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Select the outlier in the data set.\newline23,33,49,51,53,66,74,96,25223, 33, 49, 51, 53, 66, 74, 96, 252

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Q. Select the outlier in the data set.\newline23,33,49,51,53,66,74,96,25223, 33, 49, 51, 53, 66, 74, 96, 252
  1. Arrange Data Set: Arrange the data set in ascending order.\newlineThe data set is already in ascending order: 23,33,49,51,53,66,74,96,25223, 33, 49, 51, 53, 66, 74, 96, 252.
  2. Calculate IQR: Calculate the interquartile range (IQRIQR) of the data set.\newlineFirst, find the median (Q2Q2), which is the middle value when the data is ordered. For our data set, the median is 5353.\newlineNext, find the first quartile (Q1Q1), which is the median of the lower half of the data set. The lower half is 23,33,49,5123, 33, 49, 51. The median of this half is the average of 3333 and 4949, which is (33+49)/2=41(33 + 49) / 2 = 41.\newlineThen, find the third quartile (Q3Q3), which is the median of the upper half of the data set. The upper half is 66,74,96,25266, 74, 96, 252. The median of this half is the average of Q2Q200 and Q2Q211, which is Q2Q222.\newlineNow, calculate the IQR: Q2Q233.
  3. Determine Outlier Boundaries: Determine the outlier boundaries.\newlineThe lower boundary for outliers is Q11.5×IQR=411.5×44=4166=25Q1 - 1.5 \times IQR = 41 - 1.5 \times 44 = 41 - 66 = -25.\newlineThe upper boundary for outliers is Q3+1.5×IQR=85+1.5×44=85+66=151Q3 + 1.5 \times IQR = 85 + 1.5 \times 44 = 85 + 66 = 151.
  4. Identify Outliers: Identify any values outside the outlier boundaries. The value 252252 is outside the upper boundary of 151151, so it is considered an outlier.

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