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Select the outlier in the data set. \newline11,17,21,26,34,35,37,42511, 17, 21, 26, 34, 35, 37, 425

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Q. Select the outlier in the data set. \newline11,17,21,26,34,35,37,42511, 17, 21, 26, 34, 35, 37, 425
  1. Arrange Data Set: Arrange the data set in ascending order.\newlineThe data set is already in ascending order: 11,17,21,26,34,35,37,42511, 17, 21, 26, 34, 35, 37, 425.
  2. Calculate IQR: Calculate the interquartile range (IQR) of the data set.\newlineFirst, find the median (Q2Q2), which is the middle value of the data set. Since there are 88 numbers, the median will be the average of the 44th and 55th values: (26+34)/2=30(26 + 34) / 2 = 30.\newlineNext, find Q1Q1, the median of the lower half of the data set (excluding Q2Q2): (17+21)/2=19(17 + 21) / 2 = 19.\newlineThen, find Q3Q3, the median of the upper half of the data set (excluding Q2Q2): 8800.\newlineNow, calculate 8811.
  3. Determine Outlier Boundaries: Determine the outlier boundaries.\newlineThe lower boundary for outliers is Q11.5×IQR=191.5×17=1925.5=6.5Q1 - 1.5 \times IQR = 19 - 1.5 \times 17 = 19 - 25.5 = -6.5.\newlineThe upper boundary for outliers is Q3+1.5×IQR=36+1.5×17=36+25.5=61.5Q3 + 1.5 \times IQR = 36 + 1.5 \times 17 = 36 + 25.5 = 61.5.
  4. Identify Outliers: Identify any values outside the outlier boundaries.\newlineThe value 425425 is well above the upper boundary of 61.561.5, so it is considered an outlier.

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