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SD Mekar melakukan perbaikan kosen pintu kelas. Ada empat kosen pintu aluminium yang diperbaiki. Pak Janu membuat sketsa kosen pintu seperti terlihat pada gambar. Skala gambar yang digunakan Pak Janu adalah 1:70. Keempat kosen pintu kelas berukuran sama. Sketsa kusen sebagaimana gambar. Panjang aluminium minimal yang dibutuhkan untuk membuat empat buah kosen adalah .... Keliling JP =2+3+2

1212. SD Mekar melakukan perbaikan kosen pintu kelas. Ada empat kosen pintu aluminium yang diperbaiki. Pak Janu membuat sketsa kosen pintu seperti terlihat pada gambar. Skala gambar yang digunakan Pak Janu adalah 11:7070. Keempat kosen pintu kelas berukuran sama. Sketsa kusen sebagaimana gambar.\newlinePanjang aluminium minimal yang dibutuhkan untuk membuat empat buah kosen adalah .... Keliling JP =2+3+2 =2+3+2

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Q. 1212. SD Mekar melakukan perbaikan kosen pintu kelas. Ada empat kosen pintu aluminium yang diperbaiki. Pak Janu membuat sketsa kosen pintu seperti terlihat pada gambar. Skala gambar yang digunakan Pak Janu adalah 11:7070. Keempat kosen pintu kelas berukuran sama. Sketsa kusen sebagaimana gambar.\newlinePanjang aluminium minimal yang dibutuhkan untuk membuat empat buah kosen adalah .... Keliling JP =2+3+2 =2+3+2
  1. Calculate Perimeter: Calculate the actual perimeter of one door frame using the scale 1:701:70. If the drawing's perimeter is 77 units, the actual perimeter is 7×707 \times 70.\newlineCalculation: 7×70=4907 \times 70 = 490 units.
  2. Multiply by Four: Since we need aluminium for four door frames, multiply the actual perimeter of one door frame by 44. \newlineCalculation: 490×4=1960490 \times 4 = 1960 units.
  3. Verify Calculation: Check if the calculation matches the question prompt. We calculated the total length of aluminium needed for four door frames based on the scale given.

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