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Let’s check out your problem:
5
x
+
2
5
=
2
\sqrt[5]{5 x+2}=2
5
5
x
+
2
=
2
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Math Problems
Calculus
Find limits involving trigonometric functions
Full solution
Q.
5
x
+
2
5
=
2
\sqrt[5]{5 x+2}=2
5
5
x
+
2
=
2
Raise to power of
5
5
5
:
Raise both sides to the power of
5
5
5
to eliminate the fifth root.
(
5
x
+
2
)
=
2
5
(5x + 2) = 2^5
(
5
x
+
2
)
=
2
5
Calculate
2
5
2^5
2
5
:
Calculate
2
5
2^5
2
5
.
(
5
x
+
2
)
=
32
(5x + 2) = 32
(
5
x
+
2
)
=
32
Subtract to isolate
x
x
x
:
Subtract
2
2
2
from both sides to isolate the term with
x
x
x
.
\newline
5
x
=
32
−
2
5x = 32 - 2
5
x
=
32
−
2
Calculate
32
−
2
32 - 2
32
−
2
:
Calculate
32
−
2
32 - 2
32
−
2
.
\newline
5
x
=
30
5x = 30
5
x
=
30
Divide to solve for x:
Divide both sides by
5
5
5
to solve for
x
x
x
.
\newline
x
=
30
5
x = \frac{30}{5}
x
=
5
30
Calculate
30
/
5
30 / 5
30/5
:
Calculate
30
/
5
30 / 5
30/5
.
\newline
x
=
6
x = 6
x
=
6
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Question
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lim
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\newline
Choose
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answer:
\newline
(A)
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\newline
(B)
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\newline
(C)
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\newline
(D) The limit is unbounded
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What value of
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What value of
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makes the equation below true?
\newline
2
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2 y+5=21
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y
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=
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5
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14
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16
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Question
What value of
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makes the equation below true?
\newline
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