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rl'angle 
theta, au degré près. (2 poi

tan theta=-0.9004,0^(@) <= theta < 360^(@)

rl'angle θ \theta , au degré près. (22 poi\newlinetanθ=0.9004,0θ<360 \tan \theta=-0.9004,0^{\circ} \leq \theta<360^{\circ}

Full solution

Q. rl'angle θ \theta , au degré près. (22 poi\newlinetanθ=0.9004,0θ<360 \tan \theta=-0.9004,0^{\circ} \leq \theta<360^{\circ}
  1. Use Inverse Tangent: Use the inverse tangent function to find the angle in the first or fourth quadrant. θ=arctan(0.9004)\theta = \arctan(-0.9004)
  2. Calculate Angle: Calculate the angle using a calculator. θarctan(0.9004)42\theta \approx \arctan(-0.9004) \approx -42 degrees
  3. Find Quadrant Angle: Since the range for θ\theta is from 00 to 360360 degrees, we need to find the angle in the second or fourth quadrant that corresponds to the negative angle we found.\newlineθ=36042=318\theta = 360 - 42 = 318 degrees
  4. Round to Nearest Degree: Round θ\theta to the nearest degree.\newlineθ318\theta \approx 318 degrees

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