QUESTION FOUR (8 marks)There are four lakeside homes at A, B, C, and D on a man-made quadrilateral lake. There is also a circular road arour the lake that connects the four homes. (As seen in the diagram below). Each of the four families living in the homes argues that their house has the widest angled view of the lake.It is known that:i) Water pipes FA and CE run at a tangent to the circle road.ii) AF is parallel BD.iii) Lines BD and EF both run through the centre of the circle road at O.iv) Angle ∠AFO is 47∘v) Angle ∠CEO is 32∘Give geometric reasons for all your working.a) Find the value of angle ∠FOBb) Find the value of angle BD0c) Calculate which house A, B, C, or D has the widest angled view of the lake and the value of that angle.d) Given that length AF is BD1, calculate the distance around the roas from house A to house C.
Q. QUESTION FOUR (8 marks)There are four lakeside homes at A, B, C, and D on a man-made quadrilateral lake. There is also a circular road arour the lake that connects the four homes. (As seen in the diagram below). Each of the four families living in the homes argues that their house has the widest angled view of the lake.It is known that:i) Water pipes FA and CE run at a tangent to the circle road.ii) AF is parallel BD.iii) Lines BD and EF both run through the centre of the circle road at O.iv) Angle ∠AFO is 47∘v) Angle ∠CEO is 32∘Give geometric reasons for all your working.a) Find the value of angle ∠FOBb) Find the value of angle BD0c) Calculate which house A, B, C, or D has the widest angled view of the lake and the value of that angle.d) Given that length AF is BD1, calculate the distance around the roas from house A to house C.
Angle Calculation: To find the value of angle ∠FOB, we will use the fact that AF is parallel to BD and that lines BD and EF both run through the center of the circle road at O. Since AF is parallel to BD and FO is a transversal, angle ∠AFO is congruent to angle ∠FOB due to alternate interior angles in parallel lines.Angle ∠AFO is given as AF2 degrees.Therefore, angle ∠FOB is also AF2 degrees.
Angle Calculation: To find the value of angle ∠OAF, we will use the fact that angle ∠AFO is given as 47 degrees and that angle ∠OAF is the complement to angle ∠AFO because they form a right angle at point F (since FA is tangent to the circle at point F).Angle ∠OAF=90 degrees − angle ∠AFOAngle ∠OAF=90 degrees −47 degreesAngle ∠AFO1 degrees
Widest Angle View: To calculate which house has the widest angled view of the lake, we need to consider the angles at the center of the circle road. Since BD and EF are both diameters of the circle and pass through the center O, the angles at A, B, C, and D are central angles of the circle.The widest angle will be opposite the longest arc, which is the semicircle.Since angle /AFO is 47 degrees and angle /CEO is EF0 degrees, the remaining angle at O (angle EF2) is the sum of these two angles.Angle EF3Angle EF4 degrees EF5 degreesAngle EF6 degreesThe widest angle view is at house D, which is opposite to angle EF2.Angle at house EF9 degrees O0Angle at house EF9 degrees O2 degreesAngle at house O3 degrees
Distance Calculation: To calculate the distance around the road from house A to house C, we need to find the circumference of the circle road. Since AF is a tangent to the circle and is given as 1.5km, it is also the radius of the circle.The circumference of a circle is given by the formula C=2πr, where r is the radius.C=2π×1.5kmC=3πkmSince we want the distance from A to C, we need half of the circumference, as it represents the semicircle from A to C.Distance from A to C = 21CDistance from A to C = 21×3πkmDistance from A to C = 1.5πkm
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