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QUESTION FOUR (8 marks)
There are four lakeside homes at A, B, C, and D on a man-made quadrilateral lake. There is also a circular road arour the lake that connects the four homes. (As seen in the diagram below). Each of the four families living in the homes argues that their house has the widest angled view of the lake.
It is known that:
i) Water pipes FA and CE run at a tangent to the circle road.
ii) 
AF is parallel 
BD.
iii) Lines 
BD and 
EF both run through the centre of the circle road at 
O.
iv) Angle 
/_AFO is 
47^(@)
v) Angle 
/_CEO is 
32^(@)
Give geometric reasons for all your working.
a) Find the value of angle 
/_FOB
b) Find the value of angle 
/_OAF
c) Calculate which house A, B, C, or D has the widest angled view of the lake and the value of that angle.
d) Given that length AF is 
1.5km, calculate the distance around the roas from house A to house C.

QUESTION FOUR (88 marks)\newlineThere are four lakeside homes at A, B, C, and D on a man-made quadrilateral lake. There is also a circular road arour the lake that connects the four homes. (As seen in the diagram below). Each of the four families living in the homes argues that their house has the widest angled view of the lake.\newlineIt is known that:\newlinei) Water pipes FA and CE run at a tangent to the circle road.\newlineii) AF A F is parallel BD B D .\newlineiii) Lines BD B D and EF E F both run through the centre of the circle road at O O .\newlineiv) Angle AFO \angle A F O is 47 47^{\circ} \newlinev) Angle CEO \angle \mathrm{CEO} is 32 32^{\circ} \newlineGive geometric reasons for all your working.\newlinea) Find the value of angle FOB \angle F O B \newlineb) Find the value of angle BD B D 00\newlinec) Calculate which house A, B, C, or D has the widest angled view of the lake and the value of that angle.\newlined) Given that length AF is BD B D 11, calculate the distance around the roas from house A to house C.

Full solution

Q. QUESTION FOUR (88 marks)\newlineThere are four lakeside homes at A, B, C, and D on a man-made quadrilateral lake. There is also a circular road arour the lake that connects the four homes. (As seen in the diagram below). Each of the four families living in the homes argues that their house has the widest angled view of the lake.\newlineIt is known that:\newlinei) Water pipes FA and CE run at a tangent to the circle road.\newlineii) AF A F is parallel BD B D .\newlineiii) Lines BD B D and EF E F both run through the centre of the circle road at O O .\newlineiv) Angle AFO \angle A F O is 47 47^{\circ} \newlinev) Angle CEO \angle \mathrm{CEO} is 32 32^{\circ} \newlineGive geometric reasons for all your working.\newlinea) Find the value of angle FOB \angle F O B \newlineb) Find the value of angle BD B D 00\newlinec) Calculate which house A, B, C, or D has the widest angled view of the lake and the value of that angle.\newlined) Given that length AF is BD B D 11, calculate the distance around the roas from house A to house C.
  1. Angle Calculation: To find the value of angle FOB\angle FOB, we will use the fact that AFAF is parallel to BDBD and that lines BDBD and EFEF both run through the center of the circle road at OO. Since AFAF is parallel to BDBD and FOFO is a transversal, angle AFO\angle AFO is congruent to angle FOB\angle FOB due to alternate interior angles in parallel lines.\newlineAngle AFO\angle AFO is given as AFAF22 degrees.\newlineTherefore, angle FOB\angle FOB is also AFAF22 degrees.
  2. Angle Calculation: To find the value of angle OAF\angle OAF, we will use the fact that angle AFO\angle AFO is given as 4747 degrees and that angle OAF\angle OAF is the complement to angle AFO\angle AFO because they form a right angle at point F (since FA is tangent to the circle at point F).\newlineAngle OAF=90\angle OAF = 90 degrees - angle AFO\angle AFO\newlineAngle OAF=90\angle OAF = 90 degrees - 4747 degrees\newlineAngle AFO\angle AFO11 degrees
  3. Widest Angle View: To calculate which house has the widest angled view of the lake, we need to consider the angles at the center of the circle road. Since BDBD and EFEF are both diameters of the circle and pass through the center OO, the angles at AA, BB, CC, and DD are central angles of the circle.\newlineThe widest angle will be opposite the longest arc, which is the semicircle.\newlineSince angle /AFO/_AFO is 4747 degrees and angle /CEO/_CEO is EFEF00 degrees, the remaining angle at OO (angle EFEF22) is the sum of these two angles.\newlineAngle EFEF33\newlineAngle EFEF44 degrees EFEF55 degrees\newlineAngle EFEF66 degrees\newlineThe widest angle view is at house DD, which is opposite to angle EFEF22.\newlineAngle at house EFEF99 degrees OO00\newlineAngle at house EFEF99 degrees OO22 degrees\newlineAngle at house OO33 degrees
  4. Distance Calculation: To calculate the distance around the road from house A to house C, we need to find the circumference of the circle road. Since AF is a tangent to the circle and is given as 1.5km1.5 \, \text{km}, it is also the radius of the circle.\newlineThe circumference of a circle is given by the formula C=2πrC = 2 \pi r, where rr is the radius.\newlineC=2π×1.5kmC = 2 \pi \times 1.5 \, \text{km}\newlineC=3πkmC = 3 \pi \, \text{km}\newlineSince we want the distance from A to C, we need half of the circumference, as it represents the semicircle from A to C.\newlineDistance from A to C = 12C\frac{1}{2} C\newlineDistance from A to C = 12×3πkm\frac{1}{2} \times 3 \pi \, \text{km}\newlineDistance from A to C = 1.5πkm1.5 \pi \, \text{km}

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