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Find k^(')(x) if k(x)=-3x*e^(-4x^(3)+3x^(2)).

Find k(x) k^{\prime}(x) if k(x)=3xe4x3+3x2 k(x)=-3 x \cdot e^{-4 x^{3}+3 x^{2}} .

Full solution

Q. Find k(x) k^{\prime}(x) if k(x)=3xe4x3+3x2 k(x)=-3 x \cdot e^{-4 x^{3}+3 x^{2}} .
  1. Identify Components: Identify the components of the function that will require the use of the product rule and the chain rule for differentiation. The function k(x)=3xe(4x3+3x2)k(x) = -3x \cdot e^{(-4x^3 + 3x^2)} is a product of two functions, 3x-3x and e(4x3+3x2)e^{(-4x^3 + 3x^2)}. The exponential function also contains a composite function, which will require the use of the chain rule.
  2. Apply Product Rule: Apply the product rule for differentiation, which states that the derivative of a product of two functions is the derivative of the first function times the second function plus the first function times the derivative of the second function. Let u=3xu = -3x and v=e(4x3+3x2)v = e^{(-4x^3 + 3x^2)}. Then, k(x)=uv+uvk'(x) = u'v + uv'.
  3. Differentiate uu: Differentiate u=3xu = -3x with respect to xx to get u=3u' = -3.
  4. Differentiate vv: Differentiate v=e(4x3+3x2)v = e^{(-4x^3 + 3x^2)} with respect to xx using the chain rule. The chain rule states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function. Let g(x)=4x3+3x2g(x) = -4x^3 + 3x^2 be the inner function. Then, v=eg(x)g(x)v' = e^{g(x)} \cdot g'(x).
  5. Differentiate gg: Differentiate g(x)=4x3+3x2g(x) = -4x^3 + 3x^2 with respect to xx to get g(x)=12x2+6xg'(x) = -12x^2 + 6x.
  6. Substitute gg' into vv': Substitute g(x)g'(x) into the expression for vv' to get v=e(4x3+3x2)(12x2+6x)v' = e^{(-4x^3 + 3x^2)} \cdot (-12x^2 + 6x).
  7. Substitute into Product Rule: Substitute uu', vv, and vv' into the product rule expression k(x)=uv+uvk'(x) = u'v + uv' to get k(x)=3e(4x3+3x2)+(3x)(e(4x3+3x2)(12x2+6x))k'(x) = -3 \cdot e^{(-4x^3 + 3x^2)} + (-3x) \cdot (e^{(-4x^3 + 3x^2)} \cdot (-12x^2 + 6x)).
  8. Simplify Expression: Simplify the expression for k(x)k'(x) by distributing and combining like terms. k(x)=3e(4x3+3x2)3xe(4x3+3x2)(12x2+6x).k'(x) = -3e^{(-4x^3 + 3x^2)} - 3x \cdot e^{(-4x^3 + 3x^2)} \cdot (-12x^2 + 6x).
  9. Factor out Common Factor: Factor out the common factor e(4x3+3x2)e^{(-4x^3 + 3x^2)} to get k(x)=e(4x3+3x2)×(33x×(12x2+6x))k'(x) = e^{(-4x^3 + 3x^2)} \times (-3 - 3x \times (-12x^2 + 6x)).
  10. Distribute 3x-3x: Continue simplifying the expression by distributing 3x-3x inside the parentheses. k(x)=e(4x3+3x2)(3+36x318x2)k'(x) = e^{(-4x^3 + 3x^2)} \cdot (-3 + 36x^3 - 18x^2).
  11. Combine Like Terms: Combine like terms inside the parentheses to get the final expression for k(x)k'(x). k(x)=e(4x3+3x2)(36x318x23)k'(x) = e^{(-4x^3 + 3x^2)} \cdot (36x^3 - 18x^2 - 3).

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