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Question 8

1 point
The point 
A(3,5) is mapped onto 
A^(')(3,-5) by a transformation represented by the matrix 
T. The matrix 
T could be


([1,0],[1,1])quad([1,-1],[0,1])
A
B

([-1,0],[0,-1])quad([1,0],[0,-1])
C
D

Question 88\newline* 11 point\newlineThe point A(3,5) A(3,5) is mapped onto A(3,5) A^{\prime}(3,-5) by a transformation represented by the matrix T \mathrm{T} . The matrix T \mathrm{T} could be\newline(1011)(1101) \left(\begin{array}{ll} 1 & 0 \\ 1 & 1 \end{array}\right) \quad\left(\begin{array}{cc} 1 & -1 \\ 0 & 1 \end{array}\right) \newlineA\newlineB\newline(1001)(1001) \left(\begin{array}{rr} -1 & 0 \\ 0 & -1 \end{array}\right) \quad\left(\begin{array}{rr} 1 & 0 \\ 0 & -1 \end{array}\right) \newlineC\newlineD

Full solution

Q. Question 88\newline* 11 point\newlineThe point A(3,5) A(3,5) is mapped onto A(3,5) A^{\prime}(3,-5) by a transformation represented by the matrix T \mathrm{T} . The matrix T \mathrm{T} could be\newline(1011)(1101) \left(\begin{array}{ll} 1 & 0 \\ 1 & 1 \end{array}\right) \quad\left(\begin{array}{cc} 1 & -1 \\ 0 & 1 \end{array}\right) \newlineA\newlineB\newline(1001)(1001) \left(\begin{array}{rr} -1 & 0 \\ 0 & -1 \end{array}\right) \quad\left(\begin{array}{rr} 1 & 0 \\ 0 & -1 \end{array}\right) \newlineC\newlineD
  1. Question Prompt: Question prompt: Find the matrix TT that maps point A(3,5)A(3,5) onto A(3,5)A'(3,-5).
  2. Transformation Matrix Calculation: To find the transformation matrix, we need to consider how the xx and yy coordinates change. The xx-coordinate stays the same, so the first column of TT should be [1,0][1,0]. The yy-coordinate changes sign, so the second column of TT should be [0,1][0,-1].
  3. Correct Matrix Identification: Looking at the options, the matrix that has [1,0][1,0] as the first column and [0,1][0,-1] as the second column is the correct transformation matrix.
  4. Correct Matrix Identification: Looking at the options, the matrix that has [1,0][1,0] as the first column and [0,1][0,-1] as the second column is the correct transformation matrix.Option C has the matrix ([1,0],[0,1])([-1,0],[0,-1]), which flips both xx and yy coordinates, which is not what we want. Option D has the matrix ([1,0],[0,1])([1,0],[0,-1]), which keeps the xx-coordinate the same and flips the yy-coordinate, which is the transformation we're looking for.