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Question 4 If m/_NOM=60^(@), then what is the length of the minor arc NM^(⏜) ? (pi)/(4) 2pi pi (3pi)/(2) Previous Next ,

Question 44\newlineIf m∠NOM=60∘ m \angle N O M=60^{\circ} , then what is the length of the minor arc \overparen{N M} ?\newlineπ4 \frac{\pi}{4} \newline2π 2 \pi \newlineπ \pi \newline3π2 \frac{3 \pi}{2} \newlinePrevious\newlineNext ,

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Q. Question 44\newlineIf m∠NOM=60∘ m \angle N O M=60^{\circ} , then what is the length of the minor arc \overparen{N M} ?\newlineπ4 \frac{\pi}{4} \newline2π 2 \pi \newlineπ \pi \newline3π2 \frac{3 \pi}{2} \newlinePrevious\newlineNext ,
  1. Minor Arc Measure: The measure of the minor arc is the same as the measure of the angle at the center, which is 6060 degrees.
  2. Circle Circumference Calculation: The circumference of the whole circle is 2π2\pi times the radius (C=2πrC=2\pi r). Since the circle has 360360 degrees, 6060 degrees is 16\frac{1}{6} of the circle.
  3. Length of the Arc Calculation: To find the length of the arc, we take 16\frac{1}{6} of the circumference, which is (16)⋅2π=2π6(\frac{1}{6})\cdot2\pi = \frac{2\pi}{6}.
  4. Final Simplification: Simplify (2π)/6(2\pi)/6 to get π/3\pi/3.

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