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Question 2
Give the first three terms of 
(1+x)^(15) in descending order

Question 22\newlineGive the first three terms of (1+x)15 (1+x)^{15} in descending order

Full solution

Q. Question 22\newlineGive the first three terms of (1+x)15 (1+x)^{15} in descending order
  1. Recognize binomial theorem: Recognize that we need to use the binomial theorem to expand (1+x)15(1+x)^{15}. The binomial theorem states that (a+b)n(a+b)^n can be expanded into a series of terms that involve powers of aa and bb and binomial coefficients. The first term will be ana^n, the second term will be nan1bn\cdot a^{n-1}\cdot b, and the third term will be n(n1)2an2b2\frac{n\cdot(n-1)}{2}\cdot a^{n-2}\cdot b^2.
  2. Find first term: Apply the binomial theorem to find the first term of the expansion. The first term is simply 11 raised to the power of 1515, which is 11. So, the first term is 1×x01 \times x^0 or just 11.
  3. Calculate second term: Calculate the second term using the binomial theorem. The second term is 1515 times 11 raised to the power of 1414 times xx, which is 15x15*x.
  4. Calculate third term: Calculate the third term using the binomial theorem. The third term involves the binomial coefficient (15×14)/2(15 \times 14)/2, which is 105105, times 11 raised to the power of 1313 times xx squared, which is 105×x2105 \times x^2.

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