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produit de ABAB quand A=(10 32);B=(401 302)A = \begin{pmatrix} -1 & 0 \ 3 & 2 \end{pmatrix} ;B = \begin{pmatrix} 4 & 0 & 1 \ -3 & 0 & 2 \end{pmatrix}

Full solution

Q. produit de ABAB quand A=(10 32);B=(401 302)A = \begin{pmatrix} -1 & 0 \ 3 & 2 \end{pmatrix} ;B = \begin{pmatrix} 4 & 0 & 1 \ -3 & 0 & 2 \end{pmatrix}
  1. Define Matrices A and B: Step 11: Define matrices A and B. \newlineA=(10 32)A = \begin{pmatrix} -1 & 0 \ 3 & 2 \end{pmatrix}\newlineB=(401 302)B = \begin{pmatrix} 4 & 0 & 1 \ -3 & 0 & 2 \end{pmatrix}
  2. Calculate Product AB: Step 22: Calculate the product AB.\newlineTo multiply two matrices, the number of columns in the first matrix must equal the number of rows in the second matrix. Matrix AA is 2×22 \times 2 and Matrix BB is 2×32 \times 3, so we can multiply them.\newlineFirst row of ABAB:\newlineAB[1,1]=(1)(4)+(0)(3)=4AB[1,1] = (-1)(4) + (0)(-3) = -4\newlineAB[1,2]=(1)(0)+(0)(0)=0AB[1,2] = (-1)(0) + (0)(0) = 0\newlineAB[1,3]=(1)(1)+(0)(2)=1AB[1,3] = (-1)(1) + (0)(2) = -1\newlineSecond row of ABAB:\newlineAB[2,1]=(3)(4)+(2)(3)=126=6AB[2,1] = (3)(4) + (2)(-3) = 12 - 6 = 6\newline2×22 \times 200\newline2×22 \times 211

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