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Prepare 
0.5M in of 
NaCl in a (volumetric flask)ml of water ?
M.Wt

Na=23g//mol

cl=35.5g//mole

Prepare 0.5M0.5\,\text{M} in of NaCl\text{NaCl} in a (volumetric flask)ml(\text{volumetric flask})\,\text{ml} of water ? M.Wt\text{M.Wt}Na=23g/mol\text{Na}=23\,\text{g/mol}Cl=35.5g/mole\text{Cl}=35.5\,\text{g/mole}

Full solution

Q. Prepare 0.5M0.5\,\text{M} in of NaCl\text{NaCl} in a (volumetric flask)ml(\text{volumetric flask})\,\text{ml} of water ? M.Wt\text{M.Wt}Na=23g/mol\text{Na}=23\,\text{g/mol}Cl=35.5g/mole\text{Cl}=35.5\,\text{g/mole}
  1. Calculate Molar Mass: Calculate the molar mass of NaCl. \newlineNaCl = Na + Cl = 23g/mol+35.5g/mol=58.5g/mol23 \, \text{g/mol} + 35.5 \, \text{g/mol} = 58.5 \, \text{g/mol}.
  2. Determine Amount Needed: Determine the amount of NaCl needed for a 0.50.5M solution in 11 liter (10001000 ml) of water.\newlineAmount of NaCl = Molarity ×\times Molar mass ×\times Volume (in liters)\newline = 0.50.5 mol/L ×\times 58.558.5 g/mol ×\times 11 L\newline = 1100 g.
  3. Assume Solution Volume: Since the problem does not specify the volume of the solution, assume it is 11 liter for calculation purposes.

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