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\newline12\frac{1}{2}\newlineCorrect\newlineω=km\omega=\sqrt{\frac{k}{m}}. This is the formula for the angular frequency \newlineω\omega of a mass \newlinemm suspended from a spring of spring constant \newlinekk. Solve this formula for \newlinekk\newlineAnswer\newlineKeyboar

Full solution

Q. \newline12\frac{1}{2}\newlineCorrect\newlineω=km\omega=\sqrt{\frac{k}{m}}. This is the formula for the angular frequency \newlineω\omega of a mass \newlinemm suspended from a spring of spring constant \newlinekk. Solve this formula for \newlinekk\newlineAnswer\newlineKeyboar
  1. Multiply by mm: Now, we need to get rid of the division by mm. To do this, we multiply both sides of the equation by mm.\newlinem(ω)2=m(km)m \cdot (\omega)^2 = m \cdot \left(\frac{k}{m}\right)\newlineOn the right side, the mm in the numerator and the denominator cancel out, leaving us with:\newlinem(ω)2=km \cdot (\omega)^2 = k
  2. Isolate k: We have now isolated k on one side of the equation. The final equation is:\newlinek=m(ω)2k = m \cdot (\omega)^2\newlineThis is the solved equation for kk in terms of mm and ω\omega.

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