pradice $1$ $\newline$ Express in centimeters. $\newline$ (a) $4 \mathrm{~m}$ $\newline$ b) $1 \mathrm{~m}$ $\newline$ d) $3 \mathrm{~m} 95 \mathrm{~cm}$ $\newline$ e) $4 m$ $\newline$ $2$ . Express in meters and centime $\newline$ a) $120 \mathrm{~cm}$ $\newline$ b) $252$ $\newline$ d) $618 \mathrm{~cm}$ $\newline$ e) $96$ $\newline$ $3$ . Arrange the lengths in order $680 \mathrm{~cm} 6 \mathrm{~m} 85 \mathrm{~cm} \quad 6 \mathrm{~m}$ $\newline$ $4$ . Subtract.

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Math Problems

Grade 6

Convert between customary and metric systems

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Q. pradice

1

\newline

Express in centimeters.

\newline

(a)

4 \mathrm{~m}

\newline

1 \mathrm{~m}

\newline

3 \mathrm{~m} 95 \mathrm{~cm}

\newline

4 m

\newline

2

. Express in meters and centime

\newline

120 \mathrm{~cm}

\newline

252

\newline

618 \mathrm{~cm}

\newline

96

\newline

3

. Arrange the lengths in order

680 \mathrm{~cm} 6 \mathrm{~m} 85 \mathrm{~cm} \quad 6 \mathrm{~m}

\newline

4

. Subtract.

Convert to centimeters: To convert meters to centimeters, we multiply the number of meters by $100$ since there are $100$ centimeters in a meter. $\newline$ a) $4\,\text{m} = 4 \times 100\,\text{cm} = 400\,\text{cm}$ $\newline$ b) $1\,\text{m} = 1 \times 100\,\text{cm} = 100\,\text{cm}$ $\newline$ d) $3\,\text{m}95\,\text{cm} = (3 \times 100\,\text{cm}) + 95\,\text{cm} = 300\,\text{cm} + 95\,\text{cm} = 395\,\text{cm}$ $\newline$ e) $4\,\text{m} = 4 \times 100\,\text{cm} = 400\,\text{cm}$
Express in meters and centimeters: To express centimeters in meters and centimeters, we divide the number of centimeters by $100$ to get the meters, and the remainder will be the centimeters. $\newline$ a) $120\text{cm} = 1\text{m} \, 20\text{cm}$ $\newline$ b) $252\text{cm} = 2\text{m} \, 52\text{cm}$ $\newline$ d) $618\text{cm} = 6\text{m} \, 18\text{cm}$ $\newline$ e) $96\text{cm} = 0\text{m} \, 96\text{cm}$
Arrange in order: To arrange the lengths in order, we first need to convert all measurements to the same unit. We will convert everything to centimeters for comparison. $\newline$ $680\,\text{cm} = 680\,\text{cm}$ $\newline$ $6\,\text{m}85\,\text{cm} = (6 \times 100\,\text{cm}) + 85\,\text{cm} = 600\,\text{cm} + 85\,\text{cm} = 685\,\text{cm}$ $\newline$ $6\,\text{m} = 6 \times 100\,\text{cm} = 600\,\text{cm}$ $\newline$ Now we arrange them in order: $600\,\text{cm}, 680\,\text{cm}, 685\,\text{cm}$ .
Subtract lengths: To subtract, we need to clarify what values are being subtracted from what. The problem statement is not clear on this. Assuming we are subtracting the smallest value from the largest: $\newline$ $685\,\text{cm} - 600\,\text{cm} = 85\,\text{cm}$