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Perbandingan uang Abi dan uang Bima adalah 2:32 : 3, sedangkan uang Bima =45= \frac{4}{5} uang Citra. Jika selisih uang Abi dan Citra adalah Rp350.000350.000, jumlah yang Abi, Bima, dan Citra adalah ....

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Q. Perbandingan uang Abi dan uang Bima adalah 2:32 : 3, sedangkan uang Bima =45= \frac{4}{5} uang Citra. Jika selisih uang Abi dan Citra adalah Rp350.000350.000, jumlah yang Abi, Bima, dan Citra adalah ....
  1. Denote Money Ratios: Let's denote Abi's money as AA, Bima's as BB, and Citra's as CC. The ratio of Abi's to Bima's money is 2:32:3, so we can write AB=23\frac{A}{B} = \frac{2}{3}.
  2. Expressing Relationships: Bima's money is 45\frac{4}{5} of Citra's, so B=45×CB = \frac{4}{5} \times C.
  3. Substitute and Simplify: We know the difference between Abi's and Citra's money is Rp350,000350,000, so CA=350,000C - A = 350,000.
  4. Solving for C: From the ratio AB=23\frac{A}{B} = \frac{2}{3}, we can express AA as A=23×BA = \frac{2}{3} \times B.
  5. Solving for C: From the ratio A/B=2/3A/B = 2/3, we can express AA as A=23×BA = \frac{2}{3} \times B.Substitute BB from step 33 into the expression from step 55, we get A=23×(45×C)=815×CA = \frac{2}{3} \times (\frac{4}{5} \times C) = \frac{8}{15} \times C.
  6. Solving for C: From the ratio AB=23\frac{A}{B} = \frac{2}{3}, we can express AA as A=23×BA = \frac{2}{3} \times B.Substitute BB from step 33 into the expression from step 55, we get A=23×(45×C)=815×CA = \frac{2}{3} \times (\frac{4}{5} \times C) = \frac{8}{15} \times C.Now we have two expressions involving AA and CC: A=815×CA = \frac{8}{15} \times C and CA=350,000C - A = 350,000. Let's substitute AA in the second equation with the expression from the first equation: AA00.
  7. Solving for C: From the ratio AB=23\frac{A}{B} = \frac{2}{3}, we can express AA as A=23×BA = \frac{2}{3} \times B.Substitute BB from step 33 into the expression from step 55, we get A=23×(45×C)=815×CA = \frac{2}{3} \times (\frac{4}{5} \times C) = \frac{8}{15} \times C.Now we have two expressions involving AA and CC: A=815×CA = \frac{8}{15} \times C and CA=350,000C - A = 350,000. Let's substitute AA in the second equation with the expression from the first equation: AA00.Simplify the equation: AA11, which gives us AA22.
  8. Solving for C: From the ratio AB=23\frac{A}{B} = \frac{2}{3}, we can express AA as A=23×BA = \frac{2}{3} \times B.Substitute BB from step 33 into the expression from step 55, we get A=23×(45×C)=815×CA = \frac{2}{3} \times (\frac{4}{5} \times C) = \frac{8}{15} \times C.Now we have two expressions involving AA and CC: A=815×CA = \frac{8}{15} \times C and CA=350,000C - A = 350,000. Let's substitute AA in the second equation with the expression from the first equation: AA00.Simplify the equation: AA11, which gives us AA22.Solve for CC: AA44, but this is wrong because I made a calculation error. The correct calculation should be AA55.

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