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Part 33\newlineThe sum of a finite of a geometric series can be found by\newlineSn=a1(1rn)1rS_n = \frac{a_1(1-r^n)}{1-r}\newlineDerive the formula for the sum of a finite geometric series.\newline[Hint:\newlinea) Start with the general geometric series\newlineSn=a1+a1r+a1r2+a1r3++a1rn1S_n = a_1 + a_1r + a_1r^2 + a_1r^3 + \dots + a_1r^{n-1}\newlinewith common ratio \newlinerr\newlineb) Multiply both sides of this equation by \newliner-r.\newlinec) Add the results of \newlinea. and \newlineb. and then do some algebraic rearranging.]\newline1111. Find \newlineS10S_{10} for the geometric series with \newlinea1=5a_1=5 and \newliner=3r=3\newline166166

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Q. Part 33\newlineThe sum of a finite of a geometric series can be found by\newlineSn=a1(1rn)1rS_n = \frac{a_1(1-r^n)}{1-r}\newlineDerive the formula for the sum of a finite geometric series.\newline[Hint:\newlinea) Start with the general geometric series\newlineSn=a1+a1r+a1r2+a1r3++a1rn1S_n = a_1 + a_1r + a_1r^2 + a_1r^3 + \dots + a_1r^{n-1}\newlinewith common ratio \newlinerr\newlineb) Multiply both sides of this equation by \newliner-r.\newlinec) Add the results of \newlinea. and \newlineb. and then do some algebraic rearranging.]\newline1111. Find \newlineS10S_{10} for the geometric series with \newlinea1=5a_1=5 and \newliner=3r=3\newline166166
  1. General Geometric Series Formula: Let's start with the general geometric series formula:\newlineSn=a1+a1r+a1r2+a1r3++a1rn1 S_n = a_1 + a_1r + a_1r^2 + a_1r^3 + \dots + a_1r^{n-1}
  2. Multiply by Common Ratio: Now, multiply both sides of the equation by the common ratio r r :\newlinerSn=a1r+a1r2+a1r3++a1rn1+a1rn rS_n = a_1r + a_1r^2 + a_1r^3 + \dots + a_1r^{n-1} + a_1r^n
  3. Subtract Equations: Subtract the second equation from the first equation:\newlineSnrSn=a1+a1r+a1r2++a1rn1(a1r+a1r2++a1rn1+a1rn) S_n - rS_n = a_1 + a_1r + a_1r^2 + \dots + a_1r^{n-1} - (a_1r + a_1r^2 + \dots + a_1r^{n-1} + a_1r^n)
  4. Simplify Left Side: Simplify the left side of the equation:\newlineSn(1r)=a1a1rn S_n(1 - r) = a_1 - a_1r^n
  5. Solve for Sn: Now, solve for Sn S_n by dividing both sides by (1r) (1 - r) :\newlineSn=a1(1rn)1r S_n = \frac{a_1(1 - r^n)}{1 - r} \newlineThis is the formula for the sum of a finite geometric series.
  6. Substitute Values: To find S10 S_{10} for the geometric series with a1=5 a_1 = 5 and r=3 r = 3 , substitute these values into the formula:\newlineS10=5(1310)13 S_{10} = \frac{5(1 - 3^{10})}{1 - 3}
  7. Calculate Numerator and Denominator: Calculate the numerator and the denominator separately:\newlineS10=5(159049)2 S_{10} = \frac{5(1 - 59049)}{-2}
  8. Simplify Expression: Simplify the expression:\newlineS10=5(59048)2 S_{10} = \frac{5(-59048)}{-2} \newlineS10=2952402 S_{10} = \frac{-295240}{-2} \newlineS10=147620 S_{10} = 147620

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