Part 3The sum of a finite of a geometric series can be found bySn=1−ra1(1−rn)Derive the formula for the sum of a finite geometric series.[Hint:a) Start with the general geometric seriesSn=a1+a1r+a1r2+a1r3+⋯+a1rn−1with common ratio rb) Multiply both sides of this equation by −r.c) Add the results of a. and b. and then do some algebraic rearranging.]11. Find S10 for the geometric series with a1=5 and r=3166
Q. Part 3The sum of a finite of a geometric series can be found bySn=1−ra1(1−rn)Derive the formula for the sum of a finite geometric series.[Hint:a) Start with the general geometric seriesSn=a1+a1r+a1r2+a1r3+⋯+a1rn−1with common ratio rb) Multiply both sides of this equation by −r.c) Add the results of a. and b. and then do some algebraic rearranging.]11. Find S10 for the geometric series with a1=5 and r=3166
General Geometric Series Formula: Let's start with the general geometric series formula:Sn=a1+a1r+a1r2+a1r3+⋯+a1rn−1
Multiply by Common Ratio: Now, multiply both sides of the equation by the common ratio r:rSn=a1r+a1r2+a1r3+⋯+a1rn−1+a1rn
Subtract Equations: Subtract the second equation from the first equation:Sn−rSn=a1+a1r+a1r2+⋯+a1rn−1−(a1r+a1r2+⋯+a1rn−1+a1rn)
Simplify Left Side: Simplify the left side of the equation:Sn(1−r)=a1−a1rn
Solve for Sn: Now, solve for Sn by dividing both sides by (1−r):Sn=1−ra1(1−rn)This is the formula for the sum of a finite geometric series.
Substitute Values: To find S10 for the geometric series with a1=5 and r=3, substitute these values into the formula:S10=1−35(1−310)
Calculate Numerator and Denominator: Calculate the numerator and the denominator separately:S10=−25(1−59049)
Simplify Expression: Simplify the expression:S10=−25(−59048)S10=−2−295240S10=147620