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P=2l+2w Which formula shows how the length of a rectangle can perimeter and the width? A. quad I=(P)/(2)-2w B. I=(P-2w)/(2) C. quad1=(P)/(2)+w D. quad1=(p-2)/(2w)

P=2l+2w P=2 l+2 w \newlineWhich formula shows how the length of a rectangle can perimeter and the width?\newlineA. I=P2−2w \quad I=\frac{P}{2}-2 w \newlineB. I=P−2w2 I=\frac{P-2 w}{2} \newlineC. 1=P2+w \quad 1=\frac{P}{2}+w \newlineD. 1=p−22w \quad 1=\frac{p-2}{2 w}

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Q. P=2l+2w P=2 l+2 w \newlineWhich formula shows how the length of a rectangle can perimeter and the width?\newlineA. I=P2−2w \quad I=\frac{P}{2}-2 w \newlineB. I=P−2w2 I=\frac{P-2 w}{2} \newlineC. 1=P2+w \quad 1=\frac{P}{2}+w \newlineD. 1=p−22w \quad 1=\frac{p-2}{2 w}
  1. Identify Formula: Identify the formula for the perimeter of a rectangle, P=2l+2wP = 2l + 2w, where ll is the length and ww is the width.
  2. Rearrange for ll: Rearrange the formula to solve for ll. Start by isolating terms involving ll on one side:\newlineP=2l+2wP = 2l + 2w\newlineP−2w=2lP - 2w = 2l
  3. Divide and Solve: Divide both sides by 22 to solve for ll:P−2w2=l\frac{P - 2w}{2} = l
  4. Compare with Options: Compare the derived formula with the given options:\newlineA. l=P2−2wl = \frac{P}{2} - 2w (Incorrect, subtraction is outside the division)\newlineB. l=P−2w2l = \frac{P - 2w}{2} (Correct, matches our derived formula)\newlineC. l=P2+wl = \frac{P}{2} + w (Incorrect, addition of width is incorrect)\newlineD. l=p−22wl = \frac{p - 2}{2w} (Incorrect, subtraction and division are incorrect)

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