On a 40Fahrenheit day, a 25mile per hour wind creates a wind chill of 29Fahrenheit. To approximate the wind chill at various temperatures caused by a 25mile per hour wind, Elon uses this rule: take 24 less than 34 of the air temperature(Fahrenheit). If a 25mile per hour wind creates a chill of −5Fahrenheit, which of the following best approximates the corresponding air temperature?
Q. On a 40Fahrenheit day, a 25mile per hour wind creates a wind chill of 29Fahrenheit. To approximate the wind chill at various temperatures caused by a 25mile per hour wind, Elon uses this rule: take 24 less than 34 of the air temperature(Fahrenheit). If a 25mile per hour wind creates a chill of −5Fahrenheit, which of the following best approximates the corresponding air temperature?
Understand the rule: Understand the rule given by Elon for approximating the wind chill at various temperatures caused by a 25 mile per hour wind. The rule is to take 24 less than 34 of the air temperature (Fahrenheit).
Set up the equation: Set up the equation using the rule to find the air temperature when the wind chill is −5 Fahrenheit.Let T be the air temperature in Fahrenheit. According to the rule:Wind chill = (4/3)T−24We know the wind chill is −5, so we can write:−5=(4/3)T−24
Solve the equation: Solve the equation for T. Add 24 to both sides to isolate the term with T on one side: −5+24=(34)T−24+2419=(34)T
Multiply to find T: Multiply both sides by the reciprocal of 34 to solve for T.43×19=TT=457T=14.25
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