My IXLLearningAssessmentAnalytY. 11 Write a quadratic function from its vertex and another point YGVA parabola opening up or down has vertex (−2,0) and passes through (−3,41). Write equation in vertex form.Simplify any fractions.SubmitWork it outNot feeling ready yet? These can help:4Graph quadratic functions in vertex form(83)I.Solve two-step linear
Q. My IXLLearningAssessmentAnalytY. 11 Write a quadratic function from its vertex and another point YGVA parabola opening up or down has vertex (−2,0) and passes through (−3,41). Write equation in vertex form.Simplify any fractions.SubmitWork it outNot feeling ready yet? These can help:4Graph quadratic functions in vertex form(83)I.Solve two-step linear
Vertex form of parabola: Vertex form of a parabola: y=a(x−h)2+k. Given vertex (h,k)=(−2,0), so the equation becomes y=a(x+2)2.
Use point to find a: Use the point (−3,41) to find the value of a. Substitute x=−3 and y=41 into the equation: 41=a(−3+2)2.
Simplify equation: Simplify the equation: 41=a(−1)2. 41=a(1).
Solve for a: Solve for a: a=41.
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