Q. Make a table of solutions for the equation y=x2+3. Then, choose the correct graph for the equation.
Identify Equation and Plan: Identify the equation and plan to create a table of values.Equation: y=x2+3.Choose values for x: −2, −1, 0, 1, 2.
Calculate y for x=−2: Calculate y for x=−2.y=(−2)2+3=4+3=7.Table so far: (−2,7).
Calculate y for x=−1: Calculate y for x=−1.y=(−1)2+3=1+3=4.Table so far: (−2,7), (−1,4).
Calculate y for x=0: Calculate y for x=0.y=(0)2+3=0+3=3.Table so far: (−2,7), (−1,4), (0,3).
Calculate y for x=1: Calculate y for x=1.y=(1)2+3=1+3=4.Table so far: (−2,7), (−1,4), (0,3), (1,4).
Calculate y for x=2: Calculate y for x=2.y=(2)2+3=4+3=7.Table so far: (−2,7), (−1,4), (0,3), (1,4), (2,7).
Review Table and Choose Graph: Review the table and choose the correct graph.Table: (−2,7), (−1,4), (0,3), (1,4), (2,7).Graph should be a parabola opening upwards with vertex at (0,3).
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