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Make a table of solutions for the equation 
y=x^(2)+3. Then, choose the correct graph for the equation.

Make a table of solutions for the equation y=x2+3 y=x^{2}+3 . Then, choose the correct graph for the equation.

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Q. Make a table of solutions for the equation y=x2+3 y=x^{2}+3 . Then, choose the correct graph for the equation.
  1. Identify Equation and Plan: Identify the equation and plan to create a table of values.\newlineEquation: y=x2+3y = x^2 + 3.\newlineChoose values for xx: 2-2, 1-1, 00, 11, 22.
  2. Calculate yy for x=2x = -2: Calculate yy for x=2x = -2.\newliney=(2)2+3=4+3=7y = (-2)^2 + 3 = 4 + 3 = 7.\newlineTable so far: (2,7)(-2, 7).
  3. Calculate yy for x=1x = -1: Calculate yy for x=1x = -1.\newliney=(1)2+3=1+3=4.y = (-1)^2 + 3 = 1 + 3 = 4.\newlineTable so far: (2,7(-2, 7), (1,4(-1, 4).
  4. Calculate yy for x=0x = 0: Calculate yy for x=0x = 0.\newliney=(0)2+3=0+3=3y = (0)^2 + 3 = 0 + 3 = 3.\newlineTable so far: (2,7(-2, 7), (1,4(-1, 4), (0,3)(0, 3).
  5. Calculate yy for x=1x = 1: Calculate yy for x=1x = 1.\newliney=(1)2+3=1+3=4y = (1)^2 + 3 = 1 + 3 = 4.\newlineTable so far: (2,7)(-2, 7), (1,4)(-1, 4), (0,3)(0, 3), (1,4)(1, 4).
  6. Calculate yy for x=2x = 2: Calculate yy for x=2x = 2.\newliney=(2)2+3=4+3=7.y = (2)^2 + 3 = 4 + 3 = 7.\newlineTable so far: (2,7)(-2, 7), (1,4)(-1, 4), (0,3)(0, 3), (1,4)(1, 4), (2,7)(2, 7).
  7. Review Table and Choose Graph: Review the table and choose the correct graph.\newlineTable: (2,7)(-2, 7), (1,4)(-1, 4), (0,3)(0, 3), (1,4)(1, 4), (2,7)(2, 7).\newlineGraph should be a parabola opening upwards with vertex at (0,3)(0, 3).

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