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m/_1=

Find 
m/_1 and 
m/_2.


{:[m/_1=120],[m/_2=]:}

In the figure, 
m/_1=(8x+7)^(@),m/_2=(4x+14 and 
m/_4=(13 x+12). Your friend incorrectly says that 
m/_4=51. What is 
m/_4 ? What mista

m1= m \angle 1= \newline88. Find m1 m \angle 1 and m2 m \angle 2 .\newlinem1=120m2= \begin{array}{l} m \angle 1=120 \\ m \angle 2= \end{array} \newline1010. In the figure, m1=(8x+7),m2=(4x+14 m \angle 1=(8 x+7)^{\circ}, m \angle 2=(4 x+14 and m4=(13x+12) m \angle 4=(13 x+12) . Your friend incorrectly says that m4=51 m \angle 4=51 . What is m4 m \angle 4 ? What mista

Full solution

Q. m1= m \angle 1= \newline88. Find m1 m \angle 1 and m2 m \angle 2 .\newlinem1=120m2= \begin{array}{l} m \angle 1=120 \\ m \angle 2= \end{array} \newline1010. In the figure, m1=(8x+7),m2=(4x+14 m \angle 1=(8 x+7)^{\circ}, m \angle 2=(4 x+14 and m4=(13x+12) m \angle 4=(13 x+12) . Your friend incorrectly says that m4=51 m \angle 4=51 . What is m4 m \angle 4 ? What mista
  1. Find x value: First, let's find the value of xx using m/1=120m/_{1} = 120 degrees.m/1=(8x+7)m/_{1} = (8x + 7)^{\circ}120=(8x+7)120 = (8x + 7)1207=8x120 - 7 = 8x113=8x113 = 8xx=1138x = \frac{113}{8}x=14.125x = 14.125
  2. Calculate m/4m/_{4}: Now, let's plug the value of xx into m/4m/_{4} to find its measure.\newlinem/4=(13x+12)m/_{4} = (13x + 12)^{\circ}\newlinem/4=(13×14.125+12)m/_{4} = (13 \times 14.125 + 12)\newlinem/4=(183.625+12)m/_{4} = (183.625 + 12)\newlinem/4=195.625m/_{4} = 195.625
  3. Correct friend's mistake: Your friend said m/4=51m/_{4} = 51, which is incorrect because we just calculated m/4m/_{4} to be 195.625195.625.