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Solve one-step multiplication and division equations: word problems

Generalized Neyman-Pearson Lemma. Let f0(x),f1(x),⋯ ,fk(x) f_{0}(x), f_{1}(x), \cdots, f_{k}(x) be k+1 k+1 probability density functions. Let ϕ0 \phi_{0} be a test function of the form\newlineϕ0(x)={1, if f0(x)>∑j=1kajfj(x)γ(x), if f0(x)=∑j=1kajfj(x)0, if f0(x)<∑j=1kajfj(x) \phi_{0}(x)=\left\{\begin{array}{lll} 1, & \text { if } & f_{0}(x)>\sum_{j=1}^{k} a_{j} f_{j}(x) \\ \gamma(x), & \text { if } & f_{0}(x)=\sum_{j=1}^{k} a_{j} f_{j}(x) \\ 0, & \text { if } & f_{0}(x)<\sum_{j=1}^{k} a_{j} f_{j}(x) \end{array}\right. \newlinewhere aj≥0 a_{j} \geq 0 for j=1,⋯ ,k j=1, \cdots, k . Show that ϕ0 \phi_{0} maximizes\newline∫ϕ(x)f0(x)dx \int \phi(x) f_{0}(x) d x \newlineamong all ϕ,0≤ϕ≤1 \phi, 0 \leq \phi \leq 1 , such that\newline∫ϕ(x)fj(x)dx≤∫ϕ0(x)fj(x)dx,j=1,2,⋯ ,k \int \phi(x) f_{j}(x) d x \leq \int \phi_{0}(x) f_{j}(x) d x, \quad j=1,2, \cdots, k
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Math Al\newlineBest Al Homework Hel\newlineLogging in\newlineA\newlineALEKS - Jameson Colle\newlineByteLearn\newlinehttps://Mww-awu.aleks.com/alekscgi/x/Isl.exe/11o_u-IgNslkasNW88D...\newlineImport favorites\newlineMVNU Students Ho...\newlineA\newlineALEKS - Jameson C...\newlineTrigonometric Identities and Equations\newlineFinding solutions in an interval for a trigonometric equation involving an...\newline0/5 0 / 5 \newlineJameson\newlineEspañol\newlineFind all solutions of the equation in the interval [0,2π) [0,2 \pi) .\newlinecot⁡2θ3+3=0 \cot \frac{2 \theta}{3}+\sqrt{3}=0 \newlineWrite your answer in radians in terms of π \pi . If there is more than one solution, separate them with commas.\newlineθ= \theta= \newline□ \square \newlineπ□,□,… \pi \quad \square, \square, \ldots \newlineAa\newline□ \square \newlineExplanation\newlineCheck\newlineC 20242024 McGraw Hill LLC. All Rights Reserved.\newlineTerms of Use\newlinePrivacy Center\newlineAccessibility\newlineType here to search\newline60∘F 60^{\circ} \mathrm{F} \newline(11))\newline22:4949 PM\newline4/22/2024 4 / 22 / 2024
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Let x \mathrm{x} represent one number and let y \mathrm{y} represent the other number. Four times a first number decreased by a second number is −16-16 . The first number increased by twice the second number is −13-13 . Use the given conditions to write a system of equations. Solve the system and find the numbers.\newlineWrite a system of equations.\newlineA. {4x−y=−16x+y=−14 \left\{\begin{array}{l}4 x-y=-16 \\ x+y=-14\end{array}\right. \newlineB. {4x−y=−16x+2y=−13 \left\{\begin{array}{l}4 x-y=-16 \\ x+2 y=-13\end{array}\right. \newlineC. {5x+y=−14x+y=−15 \left\{\begin{array}{l}5 x+y=-14 \\ x+y=-15\end{array}\right. \newlineD. {x−5y=−15x−y=−13 \left\{\begin{array}{l}x-5 y=-15 \\ x-y=-13\end{array}\right. \newlineSolve the system and find the numbers.\newlineThe numbers are x= \mathrm{x}= □ \square and y= \mathrm{y}= □ \square \newline□ \square
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44. Marco puts $200 \$ 200 into a savings account that earns 4.5% 4.5 \% per year simple interest.\newlinea. What is the equation that represents this situation?\newliney=200(1.045)∗ y=200(1.045)^{*} \newlineb. How long will it take Marco to earn $50 \$ 50 in interest?\newline250=200(1.045)t1.25=1.045t \begin{array}{l} 250=200(1.045)^{t} \\ 1.25=1.045^{t} \end{array} \newline(C) Math By
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-o webwork.pcc.edu/wє\newline7272\newlineWEBWORK\newlinePrevious Problem\newlineProblem List\newlineNext Problem\newline(11 point)\newlineLet f(x)={2.9x+21.5−5<x<021.5−2.1x0≤x≤269.2⋅2−xx>2 f(x)=\left\{\begin{array}{ll}2.9 x+21.5 & -5<x<0 \\ 21.5-2.1 x & 0 \leq x \leq 2 \\ 69.2 \cdot 2^{-x} & x>2\end{array}\right. \newlinea. f(2)=17.3 f(2)=17.3 \newlineb. f(5)=2.1625 f(5)=2.1625 \newlinec. Solve the equation f(x)=21.3 f(x)=21.3 . All solutions should be expressed in the form x= \mathbf{x}= \qquad . If there is more than one solution, use commas to separate them.\newlinex=−229,221 \boldsymbol{x}=-\frac{2}{29}, \frac{2}{21} \newlined. The domain of f f is □ \square \newlinee. The range of f f is □ \square \newlineNote: You can earn partial credit on this problem.\newlinePreview My Answers\newlineSubmit Answers\newlineShow Me Another
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The population of City Z was 50,00050,000 in 19831983. From 19831983 to 20132013, the population of City Z doubled every 55 years. Which of the following best models PP, the population of City Z from 19831983 to 20132013, tt years after 19831983?\newlineChoose 11 answer:\newline(A) 1983198300\newline(B) 1983198311\newline(C) 1983198322\newline(D) 1983198333
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