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log_(7)49=

$\log _{7} 49=$

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Relationship between squares and square roots

Full solution

Q.

\log _{7} 49=

Problem statement: We are asked to find the logarithm of $49$ with base $7$ , which is written as $\log_7(49)$ . $\newline$ To solve this, we need to find the power to which the base $7$ must be raised to get $49$ . $\newline$ We know that $7$ squared ( $7^2$ ) equals $49$ .
Step $1$ : Therefore, $\log_7(49)$ is the exponent that we put on $7$ to get $49$ , which we have determined to be $2$ . $\newline$ So, $\log_7(49) = 2$ .

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