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log_(125)5=

log1255= \log _{125} 5=

Full solution

Q. log1255= \log _{125} 5=
  1. Find Exponent Value: We need to find the value of log1255\log_{125}5. This means we are looking for the exponent that 125125 must be raised to in order to get 55.
  2. Rewrite in Base 55: We know that 125125 is equal to 535^3. So we can rewrite the logarithm in terms of base 55: log535\log_{5^3}5.
  3. Simplify Using Property: Using the property of logarithms that logbca=1clogb(a)\log_{b^c}a = \frac{1}{c} \cdot \log_b(a), we can simplify log535\log_{5^3}5 to 13log5(5)\frac{1}{3} \cdot \log_5(5).
  4. Solve for log5\log 5: We know that logb(b)=1\log_b(b) = 1 for any base bb, because any number raised to the power of 11 is itself. Therefore, log5(5)=1\log_5(5) = 1.
  5. Substitute and Simplify: Substituting the value from the previous step, we get (13)×1(\frac{1}{3}) \times 1, which simplifies to 13\frac{1}{3}.
  6. Final Answer: So, log1255=13\log_{125}5 = \frac{1}{3}. This is our final answer.

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