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Let’s check out your problem:

log_(1.25)0.8=-t

log⁡1.250.8=−t \log _{1.25} 0.8=-t

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Full solution

Q. log⁡1.250.8=−t \log _{1.25} 0.8=-t
  1. Rewrite in Exponential Form: Rewrite the logarithmic equation in exponential form: 1.25−t=0.81.25^{-t} = 0.8
  2. Find Value of t: Find the value of tt by using the property of logarithms that log⁡b(a)=c\log_b(a) = c is equivalent to bc=ab^c = a.
  3. Use Calculator: Use a calculator to find the value of tt.

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