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Let xx and yy be functions of tt with y=7xy = 7x. If dxdt=2\frac{dx}{dt} = 2, what is dydt\frac{dy}{dt} when x=π2x = \frac{\pi}{2}?\newlineWrite an exact, simplified answer.

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Q. Let xx and yy be functions of tt with y=7xy = 7x. If dxdt=2\frac{dx}{dt} = 2, what is dydt\frac{dy}{dt} when x=π2x = \frac{\pi}{2}?\newlineWrite an exact, simplified answer.
  1. Identify Relationship: Identify the relationship between yy and xx. Given y=7xy = 7x, differentiate both sides with respect to tt to find dydt\frac{dy}{dt}.
  2. Differentiate with Respect: Differentiate y=7xy = 7x with respect to tt. Using the chain rule, dydt=7dxdt\frac{dy}{dt} = 7 \cdot \frac{dx}{dt}.
  3. Substitute Value of dx/dtdx/dt: Substitute the value of dx/dtdx/dt. Given dx/dt=2dx/dt = 2, substitute into dy/dt=7×dx/dtdy/dt = 7 \times dx/dt to get dy/dt=7×2=14dy/dt = 7 \times 2 = 14.
  4. Check Value of x: Check the value of xx. Since x=π2x = \frac{\pi}{2} does not affect the differentiation directly and we are given dxdt\frac{dx}{dt}, no need to use this value in our differentiation.

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