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In a direct variation, y=4y = 4 when x=2x = 2. Write a direct variation equation that shows the relationship between xx and yy. Write your answer as an equation with yy first, followed by an equals sign.

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Q. In a direct variation, y=4y = 4 when x=2x = 2. Write a direct variation equation that shows the relationship between xx and yy. Write your answer as an equation with yy first, followed by an equals sign.
  1. Identify general form: Identify the general form of direct variation.\newlineThe general form of direct variation is y=k×xy = k \times x, where kk is the constant of variation.
  2. Substitute values: Substitute y=4y = 4 and x=2x = 2 into the equation y=k×xy = k \times x.\newline4=k×24 = k \times 2
  3. Solve for constant: Solve the equation for the constant of variation, kk.42=(k×2)2\frac{4}{2} = \frac{(k \times 2)}{2}k=2k = 2
  4. Substitute into formula: Substitute the value of kk into the direct variation formula.\newlineSince k=2k = 2, the direct variation equation is y=2xy = 2x.

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