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Let xx and yy be functions of tt with y=4exy = 4e^x. If dxdt=14\frac{dx}{dt} = \frac{1}{4}, what is dydt\frac{dy}{dt} when x=2x = 2?\newlineWrite an exact, simplified answer.

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Q. Let xx and yy be functions of tt with y=4exy = 4e^x. If dxdt=14\frac{dx}{dt} = \frac{1}{4}, what is dydt\frac{dy}{dt} when x=2x = 2?\newlineWrite an exact, simplified answer.
  1. Identify Relationship: Identify the relationship and differentiate.\newlineGiven y=4exy = 4e^x and dxdt=14\frac{dx}{dt} = \frac{1}{4}, use the chain rule to find dydt\frac{dy}{dt}.\newlinedydt=dydxdxdt=4ex(14)\frac{dy}{dt} = \frac{dy}{dx} \cdot \frac{dx}{dt} = 4e^x \cdot \left(\frac{1}{4}\right)
  2. Use Chain Rule: Substitute x=2x = 2 into the differentiated equation.\newlinedydt=4e2(14)=e2\frac{dy}{dt} = 4e^{2} \cdot \left(\frac{1}{4}\right) = e^{2}

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