Kiana Rosenthat-Wright 05/03/24HW Soore: 52,3Et238.67 of 79.4.3⋅5pointsPoints: 0 ofCalculate the weight of the piece of steel shown in the drawing. (This steel weighs 0.283lbinI3 )The weight of the piece of steel shown in the drawing is approximately □ lb. (Round to the nearest tenth as needed.)
Q. Kiana Rosenthat-Wright 05/03/24HW Soore: 52,3Et238.67 of 79.4.3⋅5pointsPoints: 0 ofCalculate the weight of the piece of steel shown in the drawing. (This steel weighs 0.283lbinI3 )The weight of the piece of steel shown in the drawing is approximately □ lb. (Round to the nearest tenth as needed.)
Identify Volume: Identify the volume of the steel piece from the drawing.Assuming the drawing provides the volume as 38.67 cubic inches.
Calculate Weight: Use the density of steel to calculate the weight.Density of steel = 0.283lb/in3.Weight = Density × Volume = 0.283lb/in3×38.67in3.
Perform Multiplication: Perform the multiplication to find the weight.Weight = 0.283×38.67=10.9411 lb.
Round Weight: Round the weight to the nearest tenth.Rounded weight = 10.9lb.
More problems from Find indefinite integrals using the substitution